Question

我正在尝试使用Youtube发布的以下代码获取YouTube API数据。我还在print添加了我的个人API密钥和括号，但代码不起作用。当我尝试在PyCharm中运行它时，我得到：

except HttpError, e:
                    ^
SyntaxError: invalid syntax

我不明白为什么。这是代码：

#!/usr/bin/python

from apiclient.discovery import build
from apiclient.errors import HttpError
from oauth2client.tools import argparser


# Set DEVELOPER_KEY to the API key value from the APIs & auth > Registered apps
# tab of
#   https://cloud.google.com/console
# Please ensure that you have enabled the YouTube Data API for your project.
DEVELOPER_KEY = "MY_API_KEY"
YOUTUBE_API_SERVICE_NAME = "youtube"
YOUTUBE_API_VERSION = "v3"

def youtube_search(options):
  youtube = build(YOUTUBE_API_SERVICE_NAME, YOUTUBE_API_VERSION,
    developerKey=DEVELOPER_KEY)

  # Call the search.list method to retrieve results matching the specified
  # query term.
  search_response = youtube.search().list(
    q=options.q,
    part="id,snippet",
    maxResults=options.max_results
  ).execute()

  videos = []
  channels = []
  playlists = []

  # Add each result to the appropriate list, and then display the lists of
  # matching videos, channels, and playlists.
  for search_result in search_response.get("items", []):
    if search_result["id"]["kind"] == "youtube#video":
      videos.append("%s (%s)" % (search_result["snippet"]["title"],
                                 search_result["id"]["videoId"]))
    elif search_result["id"]["kind"] == "youtube#channel":
      channels.append("%s (%s)" % (search_result["snippet"]["title"],
                                   search_result["id"]["channelId"]))
    elif search_result["id"]["kind"] == "youtube#playlist":
      playlists.append("%s (%s)" % (search_result["snippet"]["title"],
                                    search_result["id"]["playlistId"]))

  print ("Videos:\n", "\n".join(videos), "\n")
  print ("Channels:\n", "\n".join(channels), "\n")
  print ("Playlists:\n", "\n".join(playlists), "\n")


if __name__ == "__main__":
  argparser.add_argument("--q", help="Search term", default="Rome")
  argparser.add_argument("--max-results", help="Max results", default=25)
  args = argparser.parse_args()

  try:
    youtube_search(args)
  except HttpError, e:
    print ("An HTTP error %d occurred:\n%s" % (e.resp.status, e.content))

Answer 1

原始代码是为python 2编写的，当你将print转换为函数（python 3必需）时，你忘了转换except块：

except HttpError as e:是python 3做异常的方法，但你也可以使用except e:，除了所有异常（可能不是你想要的）之外。

此外，您可以阅读有关python 2和3 here之间的更改的更多信息。有些人可能会让你感到惊讶！

Python 3.5 Youtube API按关键字搜索：除块外的SyntaxError

1 个答案: