我在porting over plupload into Codeigniter中取得了成功,但是当用户上传文件时,文件名如下:_1,_2,_3等。
可能导致此错误的原因是什么?
这是我的CodeIgniter控制器:
function do_upload($fileName) {
// Settings
$targetDir = getcwd() . "/uploads/";
$cleanupTargetDir = false; // Remove old files
$maxFileAge = 60 * 60; // Temp file age in seconds
// 5 minutes execution time
@set_time_limit(5 * 60);
// usleep(5000);
// Get parameters
$chunk = isset($_REQUEST["chunk"]) ? $_REQUEST["chunk"] : 0;
$chunks = isset($_REQUEST["chunks"]) ? $_REQUEST["chunks"] : 0;
// Clean the fileName for security reasons
$fileName = preg_replace('/[^\w\._]+/', '', $fileName);
// Create target dir
if (!file_exists($targetDir))
@mkdir($targetDir);
// Remove old temp files
if (is_dir($targetDir) && ($dir = opendir($targetDir))) {
while (($file = readdir($dir)) !== false) {
$filePath = $targetDir . DIRECTORY_SEPARATOR . $file;
// Remove temp files if they are older than the max age
if (preg_match('/\\.tmp$/', $file) && (filemtime($filePath) < time() - $maxFileAge))
@unlink($filePath);
}
closedir($dir);
} else
die('{"jsonrpc" : "2.0", "error" : {"code": 100, "message": "Failed to open temp directory."}, "id" : "id"}');
// Look for the content type header
if (isset($_SERVER["HTTP_CONTENT_TYPE"]))
$contentType = $_SERVER["HTTP_CONTENT_TYPE"];
if (isset($_SERVER["CONTENT_TYPE"]))
$contentType = $_SERVER["CONTENT_TYPE"];
if (strpos($contentType, "multipart") !== false) {
if (isset($_FILES['file']['tmp_name']) && is_uploaded_file($_FILES['file']['tmp_name'])) {
// Open temp file
$out = fopen($targetDir . DIRECTORY_SEPARATOR . $fileName, $chunk == 0 ? "wb" : "ab");
if ($out) {
// Read binary input stream and append it to temp file
$in = fopen($_FILES['file']['tmp_name'], "rb");
if ($in) {
while ($buff = fread($in, 4096))
fwrite($out, $buff);
} else
die('{"jsonrpc" : "2.0", "error" : {"code": 101, "message": "Failed to open input stream."}, "id" : "id"}');
fclose($out);
unlink($_FILES['file']['tmp_name']);
} else
die('{"jsonrpc" : "2.0", "error" : {"code": 102, "message": "Failed to open output stream."}, "id" : "id"}');
} else
die('{"jsonrpc" : "2.0", "error" : {"code": 103, "message": "Failed to move uploaded file."}, "id" : "id"}');
} else {
// Open temp file
$out = fopen($targetDir . DIRECTORY_SEPARATOR . $fileName, $chunk == 0 ? "wb" : "ab");
if ($out) {
// Read binary input stream and append it to temp file
$in = fopen("php://input", "rb");
if ($in) {
while ($buff = fread($in, 4096))
fwrite($out, $buff);
} else
die('{"jsonrpc" : "2.0", "error" : {"code": 101, "message": "Failed to open input stream."}, "id" : "id"}');
fclose($out);
} else
die('{"jsonrpc" : "2.0", "error" : {"code": 102, "message": "Failed to open output stream."}, "id" : "id"}');
}
// Return JSON-RPC response
die('{"jsonrpc" : "2.0", "result" : null, "id" : "id"}');
}
外部链接:
CodeIgniter
Plupload
答案 0 :(得分:1)
我知道这是一个老问题,你可能已经明白了 - 但对于像我这样遇到它的其他人: 在你的javascript函数中配置或绑定任何plupload函数 - 你传递'up'和'file'参数吗? 例如:flashuploader.bind('BeforeUpload',function(up,file){// TODO});
'up'和'file'是沿着pluploads的某个地方的成员 - 只是不确定它们来自哪里。
最初我只传入'file'数组并且名称未定义,但'id'存在 - 很奇怪。但是,在param列表中添加'up'修复了我的问题。