我有2个带有Flightdates(价格,日期,航空公司......)的多维数组。我想合并并删除具有相同日期的重复项,但我需要保持更便宜的。我总是一样的航班,但价格不同。
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答案 0 :(得分:0)
只需遍历第一个数组并匹配第二个数组中第一个数组的键的价格,然后将值推入新数组中。
第一个答案
<?php
$newArray = array();
foreach($array1 as $key =>$val)
{
if($val['price'] <= $array2[$key]['price'])
{
$newArray[] = $val;
}
else
{
$newArray[] = $array2[$key];
}
}
print_r($newArray);
?>
现场示例:CLICK HERE
第二次回答
$newArray = array();
foreach($array1 as $key => $val)
{
foreach($array2 as $k => $v)
{
if($val['date1'] == $v['date1'] && $val['date2'] == $v['date2'] && $val['airline'] == $v['airline'])
{
if($val['price'] <= $array2[$key]['price'])
{
$newArray[] = $val;
}
else
{
$newArray[] = $v;
}
}
}
}
print_r($newArray);
现场示例:CLICK HERE
这会给你:
Array
(
[0] => Array
(
[price] => 191
[date1] => 22-07-2016
[date2] => 30-07-2016
[airline] => Lufthansa
)
[1] => Array
(
[price] => 80
[date1] => 22-07-2016
[date2] => 30-07-2016
[airline] => Easyjet
)
[2] => Array
(
[price] => 200
[date1] => 22-07-2016
[date2] => 30-07-2016
[airline] => Airberlin
)
)