是否可以在Android中进行“等待秒”功能？

Question

我想做一个等待2秒的功能，然后做一些事情（显示文字）。

有没有办法做到这一点？感谢

我发布了代码，如果你能告诉我是否可能......

代码我想放的地方（已评论）

case (R.id.addPoints1):

    if(restar){

         pp1 = pp1 - 1;
         playerPoints1.setText(Integer.toString(pp1));
         restar = false;

    } else {

         pp1 = pp1 + 1;
         playerPoints1.setText(Integer.toString(pp1));

    }

    if(pp1 == 10){

         String messageString = "10 punts! Agafa la foto de la ciutat";
                    //Toast.makeText(getApplicationContext(), "10 punts! Agafa la foto de la ciutat", Toast.LENGTH_LONG);
         Snackbar message = Snackbar.make(findViewById(R.id.myLinearLayout), messageString, Snackbar.LENGTH_LONG);
         message.show();
         pp1 = 0;

         //WAIT 2 SECONDS
         playerPoints1.setText(Integer.toString(pp1));
     }
     break;

 case (R.id.addPoints2):

     if(restar){

         pp2 = pp2 - 1;
         playerPoints2.setText(Integer.toString(pp2));
         restar = false;

     }else {

         pp2 = pp2 + 1;
         playerPoints2.setText(Integer.toString(pp2));

     }

     if(pp2 == 10){

         String messageString = "10 punts! Agafa la foto de la ciutat";
         //Toast.makeText(getApplicationContext(), "10 punts! Agafa la foto de la ciutat", Toast.LENGTH_LONG);
         Snackbar message = Snackbar.make(findViewById(R.id.myLinearLayout), messageString, Snackbar.LENGTH_LONG);
         message.show();
         pp2 = 0;

         //WAIT 2 SECONDS
         playerPoints2.setText(Integer.toString(pp2));
     }
     break;

 case (R.id.addPoints3):

     if(restar){

         pp3 = pp3 - 1;
         playerPoints3.setText(Integer.toString(pp3));
         restar = false;

     }else {

         pp3 = pp3 + 1;
          playerPoints3.setText(Integer.toString(pp3));

     }

     if(pp3 == 10){

         String messageString = "10 punts! Agafa la foto de la ciutat";
         //Toast.makeText(getApplicationContext(), "10 punts! Agafa la foto de la ciutat", Toast.LENGTH_LONG);
         Snackbar message = Snackbar.make(findViewById(R.id.myLinearLayout), messageString, Snackbar.LENGTH_LONG);
         message.show();
         pp3 = 0;

         //WAIT 2 SECONDS
         playerPoints3.setText(Integer.toString(pp3));

     }
     break;

 case (R.id.addPoints4):

     if(restar == true){

          pp4 = pp4 - 1;
          playerPoints4.setText(Integer.toString(pp4));
          restar = false;

     }else {

          pp4 = pp4 + 1;
          playerPoints4.setText(Integer.toString(pp4));

     }

     if(pp4 == 10){

          String messageString = "10 punts! Agafa la foto de la ciutat";
          //Toast.makeText(getApplicationContext(), "10 punts! Agafa la foto de la ciutat", Toast.LENGTH_LONG);
          Snackbar message = Snackbar.make(findViewById(R.id.myLinearLayout), messageString, Snackbar.LENGTH_LONG);
          message.show();
          pp4 = 0;

          //WAIT 2 SECONDS
          playerPoints4.setText(Integer.toString(pp4));

      }
      break;
}

再次感谢！

Answer 1

尝试这样的事情......

new Handler().postDelayed(new Runnable() {

            @Override
            public void run() {
                // call your function
            }
        }, 2000);

Answer 2

尝试CountDown Timer：

 new CountDownTimer(20000, 1000) {

         public void onTick(long millisUntilFinished) {
             mTextField.setText("seconds remaining: " + millisUntilFinished / 1000);
         }

         public void onFinish() {
             mTextField.setText("done!");
         }
      }.start();