Question

我有一个正则表达式，确保用户名只包含a-z或A-Z或0-9中的字符，并且在3-15个字符之间。

我想为每个人单独使用正则表达式：

1）检查它是否在3-15个字符之间（任何符号任何字母;仅   重要的是不是字符）

2）必须包含来自a-z或A-Z或0-9或的字符。 _（点和   下划线）（没有空格/空格）

3）a-z或A-Z中的字符（可以包含空格/空格）

这很好用：

private static final String PASSWORD_PATTERN = "^[a-zA-Z0-9_-]{3,15}$";
etlogin_username.addValidator(new RegexpValidator("Regex wrong", USERNAME_PATTERN));

以下内容返回false：

1）USERNAME_PATTERN1为“dummyu！:)”
返回false
2）REALNAME_PATTERN为“Davic Schummer”返回false

private static final String USERNAME_PATTERN1 = "^\\w{3,15}$";
private static final String USERNAME_PATTERN2 = "^[a-zA-Z0-9_-]{3,15}$";

private static final String REALNAME_PATTERN = "^[a-zA-Z]$";

etlogin_username.addValidator(new RegexpValidator("Must be between 3-15 characters", USERNAME_PATTERN1));
etlogin_username.addValidator(new RegexpValidator("Symbols not allowed", USERNAME_PATTERN2));

etlogin_realname.addValidator(new RegexpValidator("Only alphabets allowed", REALNAME_PATTERN));

注意：我知道如何使用String.length;但是我想要一个正则表达式，因为我可以把它传递给Validator，它会处理很多其他事情

Edit1：添加了正则表达式验证器：

public class RegexpValidator extends METValidator {

  private Pattern pattern;

  public RegexpValidator(@NonNull String errorMessage, @NonNull String regex) {
    super(errorMessage);
    pattern = Pattern.compile(regex);
  }

  public RegexpValidator(@NonNull String errorMessage, @NonNull Pattern pattern) {
    super(errorMessage);
    this.pattern = pattern;
  }

  @Override
  public boolean isValid(@NonNull CharSequence text, boolean isEmpty) {
    return pattern.matcher(text).matches();
  }
}

Answer 1

试试这个

public class UsernameValidator{

          private Pattern pattern;
          private Matcher matcher;

          private static final String USERNAME_PATTERN = "^[a-z0-9_-]{3,15}$";

          public UsernameValidator(){
              pattern = Pattern.compile(USERNAME_PATTERN);
          }

          /**
           * Validate username with regular expression
           * @param username username for validation
           * @return true valid username, false invalid username
           */
          public boolean validate(final String username){

              matcher = pattern.matcher(username);
              return matcher.matches();

          }
    }

Answer 2

使用正则表达式：

private static final String PASSWORD_PATTERN = "^.{3,16}$";

private static final String USERNAME_PATTERN1 = "^.{3,16}$";
private static final String USERNAME_PATTERN2 = "^[a-zA-Z0-9._-]$";

private static final String REALNAME_PATTERN1 =  "^.{3,36}$";
private static final String REALNAME_PATTERN2 =  "^[\\p{L} .'-]+$";

Android正则表达式验证器返回false

2 个答案: