“06/08/2016 09:50:12”的日期和时间格式是什么,要转换为“dd MMMM YYYY HH:mm”?,我将NSDate转换为NSString。
答案 0 :(得分:2)
使用此代码,
NSDateFormatter* dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"dd/MM/yyyy HH:mm:ss"];
NSString *result = [dateFormat stringFromDate:date];
它为我工作,希望它有用。
答案 1 :(得分:0)
试试这段代码:
NSDateFormatter *format= [[NSDateFormatter alloc] init];
[format setDateFormat:@"dd/MM/yyyy HH:mm:ss"];
// string to date
NSString *dateStr = @"06/08/2016 01:50:12";
NSDate *date = [format dateFromString:dateStr];
// date to string
[format setDateFormat:@"dd MMMM yyyy HH:mm"];
NSString *dateStr2 = [format stringFromDate:date];
NSLog(@"%@", dateStr2);
答案 2 :(得分:-1)
试试这个,
$con = new mysqli("localhost", "root", "", "survey");
if ($con) {
printf("");
}
$query = "SELECT AVG(workarea),AVG(manager),AVG(comm) FROM score;";
// Execute multi query
if ($result = $con->query($query)) {
/* fetch object array */
while ($row = $result->fetch_row()) {
?>
<div class="row count">
WORK AREA/UNIT SCORE : <?php echo $row[0]; ?>
</div>
<div class="row count">
SUPERVISOR/MANAGER SCORE : <?php echo $row[1]; ?>
</div>
<div class="row count">
COMMUNICATION SCORE : <?php echo $row[2]; ?>
</div>
<?php
}
/* free result set */
$result->close();
}
将此日期转换为字符串:
NSString *strDate = @"06/08/2016 09:50:12";
NSDateFormatter *format= [[NSDateFormatter alloc] init];
[format setDateFormat:@"dd/MM/YYYY HH:mm:s"];
NSDate *date = [format dateFromString:strDate];
NSLog(@"%@",date);
希望这个帮助
答案 3 :(得分:-1)
NSDateFormatter *format= [[NSDateFormatter alloc] init];
[format setDateFormat:@"dd/MM/YYYY HH:mm:ss"];
// string to date
NSString *dateStr = @"06/08/2016 01:50:12";
NSDate *date = [format dateFromString:dateStr];
NSLog(@"%@", date);
// date to string
NSDate *date2 = [NSDate date];
NSString *dateStr2 = [format stringFromDate:date2];
NSLog(@"%@", dateStr2);
//@"dd/MM/YYYY HH:mm:ss"
//dd is for the day.
//MM is for the month.
//YYYY is for the year.
//HH is for the hour.
//mm is for the minute.
//ss is for the second.