Question

所有

我正在从过时的mysql_query迁移到mysqli，在此过程中，我遇到了表单更新更改的一些问题。具体来说，好像获得$ud_id的{{1}}变量不起作用。

查询将写入左外连接链接表id和empinfo，其中包含这两个链接主ID。

以下是 edit.php 页面按预期工作和加载：

headcount

这是 update.php -

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">


<div class="header">
<?php include 'header.php';?>
</div>

<center>

<?php
    // db connection
    include_once('../connection.php');

        // id pull from url
        $ID = (int)$_GET['id'];
            // get results from database
            $query = "SELECT headcount.*, empinfo.*
            FROM headcount
            LEFT OUTER JOIN empinfo
            ON headcount.id = empinfo.id
            WHERE headcount.id = '$ID'";

            $response = mysqli_query($dbc, $query);

            while($row = mysqli_fetch_array($response))

            {

                echo "<form action='update.php' method='post'>";
                echo '<div style="width:40%;padding:0 10pt 0 0;float:middle;">';
                if ($row['isActive'] === '1')
                echo '<input type="checkbox" name="ud_isActive" value="1" checked>Active<br />';
                else
                echo '<input type="checkbox" name="ud_isActive" value="0">Active<br />';
                echo '<input type="hidden" name="ud_ID" value="<?=$ID;?>">';
                echo "ID #: <input type='text' name='ud_hwid' value=". $row['id'] ." disabled readonly><br />";
                echo 'Name: <input type="text" name="ud_EmployeeName" value="'. $row["EmployeeName"] .'"><br />';
                echo '<br />';
                echo '<a href="mailto:' . $row["Email"] .'">Email</a>: <input type="text" name="ud_Email" value="'. $row["Email"] .'"><br>';
                echo '<br />';
                echo 'DOB: <input type="text" name="ud_DOB" value='. $row["DOB"] .'><br />';
                echo 'Age: <input type="text" name="ud_Age" value='. $row["Age"] .'><br />';
                if ($row['isUnderage'] === '1')
                echo '<input type="checkbox" name="isUnderage" value="1" checked>Underage<br />';
                else
                echo '<input type="checkbox" name="isUnderage" value="0">Underage<br />';
                echo '</div>';
                echo '<div style="width:40%;padding:0 10pt 0 0;float:middle;">';
                echo '<br />';
                echo 'Address: <input type="text" name="ud_StreetAddress" value="'. $row["StreetAddress"] .'"><br />';
                echo 'City: <input type="text" name="ud_City" value="'. $row["City"] .'"><br />';
                echo 'Zip Code: <input type="text" name="ud_ZipCode" value="'. $row["ZipCode"] .'"><br />';
                echo '<br />';
                echo 'Home Phone: <input type="text" name="ud_HomePhone" value="'. $row["HomePhone"] .'"><br />';
                echo 'Wireless: <input type="text" name="ud_Wireless" value="'. $row["Wireless"] .'"><br />';
                echo '<br />';
                echo 'Home Department: <input type="text" name="ud_HomeDept" value="'. $row["HomeDept"] .'"><br />';
                echo 'Department Manager: <input type="text" name="ud_Manager" value="'. $row["Manager"] .'"><br />';
                echo '</div>';
                echo '<br />';
                echo 'Live Orientation:<input type="date" name="LODate" value=""><br />';
                echo '<br />';
                echo 'Online Training: <input type="date" name="OTTraining" value=""><br />';



          }

    ?>
    <br />

    <input type="Submit">
    </form> <br />
      <a href="javascript:history.back()">Go Back</a>
    <br />
    </body>
    </html>

在 update.php 的第52行，你会注意到我使用echo <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <style type="text/css"> #wrap { width:600px; margin:0 auto; } #left_col { float:left; width:300px; } #right_col { float:right; width:300px; } </style> <div class="header"> <?php include 'header.php';?> </div> <center> <?php $ud_ID = $_REQUEST["ID"]; $ud_EmployeeName = $_POST["ud_EmployeeName"]; $ud_Email = $_POST["ud_Email"]; $ud_DOB = $_POST["ud_DOB"]; $ud_Age = $_POST["ud_Age"]; $ud_StreetAddress = $_POST["ud_StreetAddress"]; $ud_City = $_POST["ud_City"]; $ud_ZipCode = $_POST["ud_ZipCode"]; $ud_HomePhone = $_POST["ud_HomePhone"]; $ud_Wireless = $_POST["ud_Wireless"]; $ud_HomeDept = $_POST["ud_HomeDept"]; $ud_Manager = $_POST["ud_Manager"]; // db connection include_once('../connection.php'); $query = "UPDATE headcount SET EmployeeName = '$ud_EmployeeName', Email = '$ud_Email', DOB = '$ud_DOB', Age = '$ud_Age', StreetAddress = '$ud_StreetAddress', City = '$ud_City', ZipCode = '$ud_ZipCode', HomePhone = '$ud_HomePhone', Wireless = '$ud_Wireless', HomeDept = '$ud_HomeDept', Manager = '$ud_Manager' WHERE ID = '$ud_ID'"; $response = mysqli_query($dbc, $query); echo $ud_ID; echo $ud_EmployeeName; if ($response) echo '<p>Record Updated<p> <br /> <a href="javascript:history.back()">Go Back</a>'; else echo "Problem updating record. MySQL Error: " . mysql_error(); ?> </body> </html>和$ud_ID - 这是为了告诉我变量显示的内容。出现$ud_EmployeeName而$ud_EmployeeName则没有。

我也尝试过使用

$ud_ID

我没有结果。

此外，在 edit.php 上，我尝试过：

$ud_ID = $_POST["ID"];

我收到错误：

echo '<input type="hidden" name="ud_ID" value='. $row["id"] .'><br />';

当我单击Notice: Undefined index: ID in update.php on line 27按钮时，我收到记录已更新的消息，但在刷新时，记录具有相同的数据。

Answer 1

您可以使用name属性获取值

$ud_ID = $_POST['ud_ID'];

表单更新 - 不起作用

1 个答案: