Question

我正在使用PHP从我的数据库（MYSQL）中检索内容。以下是我的PHP脚本：

<?php
$username = "**";
$password = "**";
$host = "**";
$database="**";

$server = mysql_connect($host, $username, $password);
$connection = mysql_select_db($database, $server);

$myquery = "
SELECT  * FROM  data1
";
    $query = mysql_query($myquery);
if ( ! $query ) {
    echo mysql_error();
    die;
}

$data = array();

for ($x = 0; $x < mysql_num_rows($query); $x++) {
    $data[] = mysql_fetch_assoc($query);
}

echo json_encode($data);

mysql_close($server);
?>

输出是完美格式化的JSON对象：

[{"ID":"1","Country":"India","Value1":"100","Value2":"200"},{"ID":"2","Country":"India","Value1":"230","Value2":"800"},{"ID":"3","Country":"USA","Value1":"30","Value2":"300"},{"ID":"4","Country":"Sri Lanka","Value1":"320","Value2":"330"},{"ID":"5","Country":"Sri Lanka","Value1":"120","Value2":"90"},{"ID":"6","Country":"Sri Lanka","Value1":"420","Value2":"890"},{"ID":"7","Country":"China","Value1":"20","Value2":"890"},{"ID":"8","Country":"China","Value1":"430","Value2":"999"},{"ID":"9","Country":"Canada","Value1":"200","Value2":"319"},{"ID":"10","Country":"Canada","Value1":"1000","Value2":"29"}]

我想使用这个JSON对象作为我的D3.js图的输入。

当我尝试创建我的D3图表时，我在浏览器日志中收到错误：

SyntaxError: Unexpected token < in JSON at position 0(…)

以下是我的D3代码，我调用PHP文件并尝试解析JSON：

d3.json("1.php", function(error, data) {
console.log(error);
//parsing operations

});

任何指针都将不胜感激。感谢

无法使用PHP

0 个答案: