Question

我正在使用JQuery Ajax（我确信自上次使用它以来情况发生了变化）但是我无法从PHP变量中提取信息。基本上我正在获取IP地址并记录IP完全加载页面然后显示它需要多长时间。

这是我的代码......

getIP.php

<?php
    if (!empty($_SERVER['HTTP_CLIENT_IP']))
    {
        $ip = $_SERVER['HTTP_CLIENT_IP'];
    }
    elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR']))
    {
        $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
    }
    else 
    {
        $ip = $_SERVER['REMOTE_ADDR'];
    }
    echo json_encode(array('ip' => $ip));
?>

调用它的事件监听器

var IPAddresses = [];

//Anonymous functions - used for quality control and logging

(function() { //Used to test how long it took for a user to connect - uses a php script with it
    window.addEventListener("load", function() {
        $.ajax({
            url: '../php/getIP.php',
            type: 'POST',
            success: function(result) 
            {
                setTimeout(function alertUser(){IPAddresses.push(result.ip);}, 40);
            }
        });
    }, false);
})();
(function() {
    window.addEventListener("load", function() {
        setTimeout(function() {
            for (var i = 0; i < IPAddresses.length; i++)
            {
                var timing = performance.timing;
                console.log(IPAddresses[i] + " " + timing.loadEventEnd - timing.responseEnd);
            }
        }, 0);
    }, false);
})();

修改

现在我没有收到错误，但它似乎没有打印IP地址或将其推入数组中。我基本上试图让它[ip] [loadtime]它给出NaN错误

Answer 1

您的输出是一个字符串：

echo $ip; //Just to check if it worked - it shows the IP
      ^---e.g. 127.0.0.1

然后您尝试将其视为数组：

setTimeout(function alertUser(){alert(result['ip']);}, 40);
                                            ^^^^^^

由于它不是一个阵列，这不会起作用。试试alert(result)。

Answer 2

尝试使用“json_encode”

IntVector2

和ajax

<html>
<body>
<center>
<form method="POST">
Enter New Password:<input type="password" name="password"/><br \>
Confirm Password:<input type="password" name="conpassword"/><br \>
<button name="submit" value="Change My Password"/>
<button type="clear"/>
</form>
</center>
</body>
</html>
<?php
@mysql_connect("localhost","root","");
mysql_select_db("sarath");
if(isset($_POST['submit']))
{

session_start();
if(!isset($_SESSION['name']))
header("location:login.php");
$n=$_SESSION['name'];
$p=$_POST['password'];
$cp=$_POST['conpassword'];
if($p==$cp)
{
 $query="UPDATE student
         SET password='$p'
         WHERE username='$n';";
 $r=mysql_query($query);
     if($r)
         echo "password changed successfully";
}
else
    echo "please enter the same password";
}
else
echo "something wrong";
?>

无法从PHP变量中获取值

2 个答案: