想象一下,我有以下NSDictionary
dict = {
"a" = [
obj1,
obj2,
obj3
],
"b" = [
obj4,
obj5
],
"invalid" = [
obj6,
obj7,
obj8
],
"c" = [
obj9,
obj10,
obj11
]
}
此数据用于使用以下TableView
中的部分填充NSArray
:
arr = @[@"A", @"B", @"C", @"D", @"E", @"F", @"G", @"H", @"I", @"J", @"K", @"L", @"M", @"N", @"O", @"P", @"Q", @"R", @"S", @"T", @"U", @"V", @"W", @"X", @"Y", @"Z"];
我使用以下方法查找对象
- (void)selectRowWithId:(NSNumber *)uid {
[dict enumerateKeysAndObjectsUsingBlock:^(id _Nonnull key, id _Nonnull obj, BOOL * _Nonnull stop) {
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(id == %@)", uid];
NSArray *filteredDictArray = [obj filteredArrayUsingPredicate:predicate];
if ([filteredDictArray count] > 0) {
NSIndexPath *targetIndexPath = nil;
//trying to find the NSIndexPath here
[[self tableView] selectRowAtIndexPath:targetIndexPath animated:NO scrollPosition:UITableViewScrollPositionMiddle];
[self tableView:[self tableView] didSelectRowAtIndexPath:targetIndexPath];
}
}];
}
假设我将对象设置为obj10
。
根据我的NSDictionary
和NSArray
,NSIndexPath
为Section:2 Row:1
如果我只知道obj10
?
所以,结合每个人的答案背后的想法和我自己的答案,以下我用过以防万一对某人有帮助。 BTW:这适用于iOS9
- (void)selectRowWithId:(NSNumber *)uid {
[dict enumerateKeysAndObjectsUsingBlock:^(id _Nonnull key, id _Nonnull obj, BOOL * _Nonnull stop) {
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(id == %@)", uid];
NSArray *filteredDictArray = [obj filteredArrayUsingPredicate:predicate];
if ([filteredDictArray count] > 0) {
//trying to find the NSIndexPath here
NSIndexPath *targetIndexPath = [NSIndexPath indexPathForRow:[[dict objectForKey:key] indexOfObject:filteredPersonsArray[0]] inSection:[arr indexOfObject:key]];
[[self tableView] selectRowAtIndexPath:targetIndexPath animated:NO scrollPosition:UITableViewScrollPositionMiddle];
[self tableView:[self tableView] didSelectRowAtIndexPath:targetIndexPath];
}
}];
}
答案 0 :(得分:1)
你的代码有点太棘手了。有时通常的循环更容易。
[dict enumerateKeysAndObjectsUsingBlock:^(id key, id obj, BOOL * stop)
{
for( NSInteger index = 0; index < [obj count]; index++ )
{
if ([obj[index] isEqualToString:uid])
{
// thats the index
// Let's have a look-up for the section
NSString *sectionKey = [[key substringToIndex:1] uppercaseString]; //Typo
for( NSInteger section=0; section < [arr count]; section++ )
{
if( [arr[section] isEqualToString:sectionKey] )
{
// That's the section
}
}
}
}
}
输入Safari。