我关注stackOverflow回答并编写代码,但我不知道发生了什么。它不会起作用。 PLZ,任何人都可以为我解决。我用愚蠢的代码......
NSMutableArray *movieDate;
NSArray *temp1 = [_dicUpcomingMovie objectForKey:@"results"];
for (NSDictionary *temp2 in temp1)
{
NSDateFormatter *formatter = [[NSDateFormatter alloc]init];
NSString *datestring = [temp2 valueForKey:@"release_date"];
//NSDate *myDate = [[NSDate alloc]init];
[formatter setDateFormat:@"dd MMM,YYYY"];
NSDate *date = [formatter dateFromString:datestring];
NSLog(@"%@",date);
[movieDate addObject:date];
NSLog(@"%@",movieDate);
}
所以就是这样。上面的代码不起作用myDate对象仍然没有
答案 0 :(得分:0)
我认为datestring
与您指定的格式不符。有关完整示例,请参阅NSDateFormatter
。
答案 1 :(得分:0)
NSMutableArray *movieDate=[[NSMutableArray alloc]init];;
NSArray *temp1 = [_dicUpcomingMovie objectForKey:@"results"];
NSDateFormatter *formatter = [[NSDateFormatter alloc]init];
for (int i=0 ;i<temp1.count;i++)
{
NSString *datestring = [[temp1 objectatindex:i]valueForKey:@"release_date"];
[serverFormatter setTimeZone:[NSTimeZone localTimeZone]];
[serverFormatter setDateFormat:@"dd,MMM,YYYY"];
NSDate *date = [serverFormatter dateFromString:dateString1];
[movieDate addObject:date];
}
NSLog(@"%@",movieDate);
答案 2 :(得分:-1)
试试这个,
NSMutableArray *movieDate;
NSArray *temp1 = [_dicUpcomingMovie objectForKey:@"results"];
for (NSDictionary *temp2 in temp1)
{
NSDateFormatter *formatter = [[NSDateFormatter alloc]init];
NSString *datestring = [temp2 valueForKey:@"release_date"];
//NSDate *myDate = [[NSDate alloc]init];
[formatter setDateFormat:@"dd MM,YYYY"];
NSDate *date = [formatter dateFromString:datestring];
NSLog(@"%@",date);
[movieDate addObject:date];
NSLog(@"%@",movieDate);
}