我想知道如何获得这种时间格式..我想要一个日期计数定时器就像链接上的这个...
任何答案或建议将不胜感激。谢谢,期待您的回复。
$(function(){
var calcNewYear = setInterval(function(){
date_started = new Date("June 15, 2008");
date_now = new Date();'
seconds = Math.floor((date_now - (date_started))/1000);
minutes = Math.floor(seconds/60);
hours = Math.floor(minutes/60);
days = Math.floor(hours/24);
years = Math.floor(days/365);
days = days -(years*365);
hours = hours-(years*365*24)-(days*24);
minutes = minutes-(years*365*24*60)-(days*24*60)-(hours*60);
seconds = seconds-(years*365*24*60*60)-(days*24*60*60)-(hours*60*60)-(minutes*60);
$("#mission").text( years + "Years |" + days + "Days |" + hours + "Hours |" + seconds + "Seconds");
},1000);
});
答案 0 :(得分:0)
对于闰年 - 使用模数选项来检查它是否为4的倍数,然后使用if条件并将365天更改为366 JsFiddle以供参考 - https://jsfiddle.net/Nagasai_Aytha/2f30178y/2/
if (years % 4 == 0) {
days = days - (years * 366);
hours = hours - (years * 366 * 24) - (days * 24);
minutes = minutes - (years * 366 * 24 * 60) - (days * 24 * 60) - (hours * 60);
seconds = seconds - (years * 366 * 24 * 60 * 60) - (days * 24 * 60 * 60) - (hours * 60 * 60) - (minutes * 60);
} else {
days = days - (years * 365);
hours = hours - (years * 365 * 24) - (days * 24);
minutes = minutes - (years * 365 * 24 * 60) - (days * 24 * 60) - (hours * 60);
seconds = seconds - (years * 365 * 24 * 60 * 60) - (days * 24 * 60 * 60) - (hours * 60 * 60) - (minutes * 60);
}
答案 1 :(得分:0)
我已经尝试过此代码。希望它可以帮助其他遇到我同样问题的人。
epsilon