Question

尝试在PHP中编写一般的4位字母数字系列。

模式如下
0000
0001
....
....
9999
A000
A001
....
....
A999
B000
....
....
Z999
AA00
....
....
AA99
AB00
....
....
ZZ99
AAA0
....
....
AAA9
AAB0
....
....
ZZZZ

我试图根据Z和no中的9来制作逻辑，但是没有任何具体的结果。

我正在尝试编写一个代码，在输入系列的最后一个数字时会返回下一个系列编号。

任何提示或线索都将受到赞赏

Answer 1

使用PHP的内置increment operator时，这实际上非常容易，它能够处理像这样的字母数字序列。

需要手动处理两个边界异常：

进行从数字到字母数字的第一次跳转
终止系列

<?php

function getNext($input){

  // boundary cases
  switch($input){

    // bridge numeric to alphanumeric
    case '9999': return 'A000';

    // terminate sequence, instead of expanding to 5 digits 'AAAA0'
    case 'ZZZ9': return 'ZZZA';

    // start over
    case 'ZZZZ': return '0000';

  }

  // normal increment
  $input = substr(++$input,0,4);

  // pad with leading zeros
  return str_pad($input, 4, '0', STR_PAD_LEFT);

}

$samples = [
  '0000','9999','A000','A999','Z999','AA99',
  'ZZ99','AAA9','ZZZ9','ZZZA','ZZZY','ZZZZ'
];

foreach ($samples as $sample)
  echo $sample . ' -> ' . getNext($sample) . PHP_EOL;

  <00> 0000 - ＆gt; 0001
  9999 - ＆gt; A000
  A000 - ＆gt; A001
  A999 - ＆gt; B000
  Z999 - ＆gt; AA00
  AA99 - ＆gt; AB00
  ZZ99 - ＆gt; AAA0
  AAA9 - ＆gt; AAB0
  ZZZ9 - ＆gt; ZZZA
  ZZZA - ＆gt; ZZZB
  ZZZY - ＆gt; ZZZZ
  ZZZZ - ＆gt; 0000

See this related answer.

Answer 2

您可以尝试这样的事情：

<?php

function generateNext($input) {
    $numbers = (int) preg_replace('/[^0-9]/', '', $input);
    $letters = preg_replace('/[^a-zA-Z]/', '', $input);

    if($numbers >= 99) 
    {
        $letters = ++$letters;
        $numNumbers = 4 - strlen($letters);
        if($numNumbers === 0) 
        {
            $numbers = "";
        }
        else
        {
            $numbers = str_pad("1", $numNumbers, "0", STR_PAD_LEFT);
        }

        $final = $letters.$numbers;
    }
    else if($input == "ZZZ9")
    {
        $final = "ZZZZ";
    }
    else 
    {
        $numbers = ++$numbers;
        $numNumbers = 4 - strlen($letters);
        if($numNumbers === 0) 
        {
            $numbers = "";
            $letters = ++$letters;
        }
        else
        {
            $numbers = str_pad($numbers, $numNumbers, "0", STR_PAD_LEFT);
        }

        $final = $letters.$numbers;
    }

    return $final;

}

?>

编码一般的4位数字数字系列

2 个答案: