Question

我的问题看似简单，希望我能尽快找到答案为了总结我的代码，我生成一个介于1和1之间的随机数。 2.根据随机数，我有一个包含questionName或easy1（easy2）的字符串"easy" + randomNum。我想打印questionName的内容，但不是字符串，而是获取数组easy1[0]或easy2[0]。

public void generateQuestion() {
    int min = 1;
    int max = 2;


    Random r = new Random();
    int questionToBeSelected = r.nextInt(max - min + 1) + min;

    System.out.println(questionToBeSelected);

    String questionName = "easy" + questionToBeSelected;

    String[] easy1 = {
            "In The Phantom Menace, who are the first two characters on screen?", //Question, obviously
            "3", //The array child that is correct
            "Padme and Annie", //Answer 1
            "Obi-Wan and Qui-Gon Jinn", //Answer 2
            "Jar Jar Binks", //Answer 3
            "Annie and Obi-Wan" //Answer 4
    };

    String[] easy2 = {
            "Sample question",
            "2",
            "Sample answer",
            "Sample answer",
            "Sample answer",
            "Sample answer",
    };

    System.out.println(easy1[0]);

    TextView questionPlaceholder = (TextView) findViewById(R.id.game_question);
    questionPlaceholder.setText(questionName[0]);  //   <-------- Problem :(

    String alreadyPlayedQuestions;
    String questionNumber;
}

由于

Answer 1

请您查看以下内容：

public void generateQuestion() {
    int min = 0;
    int max = 1;
    Random r = new Random();
    int questionToBeSelected = r.nextInt(max - min + 1) + min;
    System.out.println(questionToBeSelected);
    String[] easy1 = {
            "In The Phantom Menace, who are the first two characters on screen?", //Question, obviously
            "3", //The array child that is correct
            "Padme and Annie", //Answer 1
            "Obi-Wan and Qui-Gon Jinn", //Answer 2
            "Jar Jar Binks", //Answer 3
            "Annie and Obi-Wan" //Answer 4
    };
    String[] easy2 = {
            "Sample question",
            "2", // array index that is correct
            "Sample answer",
            "Wrong answer1",
            "Wrong answer2",
            "Wrong answer3",
    };
    String[] questionName = new String[][]{easy1, easy2}[questionToBeSelected];
    System.out.println(easy1[0]);
    TextView questionPlaceholder = (TextView) findViewById(R.id.game_question);
    System.out.println(questionName[0]);
    questionPlaceholder.setText(questionName[0]);  //   <-------- Problem :(
    String alreadyPlayedQuestions;
    String questionNumber;
}

您的方法几乎没有变化。请告诉我这是你想要达到的目的。

Answer 2

将两个数组存储在另一个数组中并从中选择一个随机元素会更容易：

int questionToBeSelected = r.nextInt(1);

String[] easy1 = {
        "In The Phantom Menace, who are the first two characters on screen?", //Question, obviously
        "3", //The array child that is correct
        "Padme and Annie", //Answer 1
        "Obi-Wan and Qui-Gon Jinn", //Answer 2
        "Jar Jar Binks", //Answer 3
        "Annie and Obi-Wan" //Answer 4
};

String[] easy2 = {
        "Sample question",
        "2",
        "Sample answer",
        "Sample answer",
        "Sample answer",
        "Sample answer",
};

String[][] easy = {easy1, easy2};

String[] selectedQuetion = easy[questionToBeSelected];

str的内容作为数组的名称

2 个答案: