Question

以下是代码：

proc ChangeColumnNumber1
    inc [FirstColumnArray]
    mov [Player1Drawx], 25h
    mov [Player1Drawy], 87h
    jmp DrawPlayer1Disc
endp ChangeColumnNumber1

DrawPlayer1Loop:
    mov bh,0h
    mov cx,[Player1Drawx]
    mov dx,[Player1Drawy]
    mov al,[player1disccolor]
    mov ah,0ch
    int 10h
    inc [Player1Drawx]
    cmp cx, [Player1Drawx + 14h]
    jl DrawPlayer1Loop

DrawPlayer1Disc: 
    mov bh, 0h
    inc [Player1Drawy] 
    cmp dx, [Player1Drawy + 14h]
    jl DrawPlayer1Loop

proc CheckPlayer2Number
    mov ah, 7
    int 21h
    cmp al, 31h
    je Player2CheckColumn1
    jmp CheckPlayer2Number
endp CheckPlayer2Number

proc Player2CheckColumn1
    cmp [FirstColumnArray], 0
    je ChangeColumnNumber2
    cmp [FirstColumnArray + 1], 0
    je ChangeColumnNumber2
endp Player2CheckColumn1

proc ChangeColumnNumber2
    inc [FirstColumnArray + 1]
    mov [Player2Drawx], 25h
    mov [Player2Drawy], 60h
    jmp DrawPlayer2Disc
endp ChangeColumnNumber2

DrawPlayer2Loop:
    mov bh,0h
    mov cx,[Player2Drawx]
    mov dx,[Player2Drawy]
    mov al,[player2disccolor]
    mov ah,0ch
    int 10h
    inc [Player2Drawx]
    cmp cx, [Player2Drawx + 14h]
    jl DrawPlayer2Loop

DrawPlayer2Disc: 
    mov bh, 0h
    inc [Player2Drawy]
    cmp dx, [Player2Drawy + 14h]
    jl DrawPlayer2Loop

当我执行它时，我应该按'1'。当我这样做时它应该绘制一个正方形，当我应该再次按'1'时，它不会绘制第二个正方形。我不明白为什么它不起作用。在此之前，我有一个mov命令，它将一个值移动到例如Player1Drawx中，但它不能用于我的新代码，所以我将其删除。

感谢您的帮助。

Answer 1

proc ChangeColumnNumber1
    inc [FirstColumnArray]
    mov [Player1Drawx], 25h
    mov [Player1Drawy], 87h
    jmp DrawPlayer1Disc
endp ChangeColumnNumber1

当jmp DrawPlayer1Disc未设置DX注册时，您仍然可以立即在cmp dx, [Player1Drawy + 14h]中使用它。

DrawPlayer1Disc: 
  mov bh, 0h
  inc [Player1Drawy] 
  mov dx, [Player1Drawy]         <<< Don't you need this?
  cmp dx, [Player1Drawy + 14h]
  jl DrawPlayer1Loop
  ret                            <<< Aren't you missing a return here?

同样适用于 DrawPlayer2Disc 。

大会 - 无法理解什么是错的

1 个答案: