Question

有人可以提供帮助，我需要从所有字段值为％someString％的字段中获取所有值。我的表有17个字段，我不想在查询中写入所有字段。 DB Mysql。

select * from Deputes_APPEAL where filePath, checkForPlagiarism, contentOfResolution, countOfPages, dateForCheck, incomeNumber, incomingDate, mainWorker, nameAndAddressOfApplicant, nameOfDepute, outDate, outNumber, result, secondaryWorkers, shortContentOfAppeal, statusOfWorking, themeOfAppeal, TypeOfDeputeAppeal, unitWhoDoResolution like %someString%

Answer 1

您可以通过以下方式实现这一目标：

SELECT 
CONCAT('SELECT * FROM Deputes_APPEAL WHERE ',GROUP_CONCAT(COLUMN_NAME SEPARATOR ' LIKE \'%something%\' OR '),' LIKE \'%something%\'')
FROM information_schema.COLUMNS 
WHERE TABLE_SCHEMA = 'YOUR_DATABASE_NAME'
AND TABLE_NAME = 'YOUR_TABLE_NAME'
AND COLUMN_NAME NOT IN ('Column1','Column2',....);

注意：您需要将列名放在NOT IN子句中，以便在LIKE表达式中省略。

输出：通过运行上述查询，您将获得如下输出：

SELECT * FROM Deputes_APPEAL WHERE column_name1 LIKE '%something%' OR .......

现在抓住这个查询并运行。

Answer 2

使用循环构建SQL - 超级简单。

final String[] properties = new String[] { /* all your fields here */ };

// build the SQL
StringBuilder sb = new StringBuilder();
sb.append( "SELECT o FROM YourEntity o " );
if ( properties.length > 0 ) {
  sb.append( "WHERE ( " ).append( properties[0] ).append( "LIKE :v0" );
  for ( int i = 1; i < properties.length; ++i ) {
    sb.append( " OR " ).append( properties[i] ).append( "LIKE :v" ).append(i); 
  }
  sb.append( " ) " );
}

// build the query.
Query query = session.createQuery( sb.toString() );
for ( int i = 0; i < properties.length; ++i ) {
  query.setParameter( "v" + i, "%something%" );
}

选择所有字段值，其中所有fileds值都像一些String

2 个答案: