在Linux中使用重定向时如何使用ProcessBuilder

时间:2016-06-12 03:12:24

标签: java linux processbuilder

我想使用ProcessBuilder运行此命令:

sort -m -u -T /dir -o output <(zcat big-zipped-file1.gz | sort -u) <(zcat big-zipped-file2.gz | sort -u) <(zcat big-zipped-file3.gz | sort -u) 

我尝试了以下内容:

// This doesn't recognise the redirection.
String[] args = new String[] {"sort", "-m", "-u", "-T", "/dir", "-o", "output", "<(zcat big-zipped-file1.gz | sort -u)", "<(zcat big-zipped-file2.gz | sort -u)", "<(zcat big-zipped-file3.gz | sort -u)"};

// This gives:
// /bin/sh: -c: line 0: syntax error near unexpected token `('
String[] args = new String[] {"/bin/sh", "-c", "\"sort -m -u -T /dir -o output <(zcat big-zipped-file1.gz | sort -u) <(zcat big-zipped-file2.gz | sort -u) <(zcat big-zipped-file3.gz | sort -u)\""};

我正在使用args,如下所示:processBuilder.command(args);

1 个答案:

答案 0 :(得分:0)

我终于明白了。罗马在评论中提到,sh不理解重定向,所以我不得不使用bash。我还必须同时使用输入流和错误流。

String[] args = new String[] {"/bin/bash", "-c", "sort -m -u -T /dir -o output <(zcat big-zipped-file1.gz | sort -u) <(zcat big-zipped-file2.gz | sort -u) <(zcat big-zipped-file3.gz | sort -u)"};

ProcessBuilder builder = new ProcessBuilder();
builder.command(args);
Process process = builder.start();
BufferedReader input = new BufferedReader(new InputStreamReader(process.getInputStream()));
BufferedReader error = new BufferedReader(new InputStreamReader(process.getErrorStream()));
while((line = input.readLine()) != null);
while((line = error.readLine()) != null);

process.waitFor();