Question

我正在编写多线程程序，可以同时从多个用户访问，程序必须避免竞争条件。

代码/多线程：

public class DataProcessor implements Serializable, Runnable {

private static final long serialVersionUID = 1L;

public DataProcessor() {

}

@Override
public void run() {
    process();
}

private void process() {

    int iSize = 5;

    for (int iCounter = 0; iCounter < iSize; iCounter++) {
        DataKey objDataKey = new DataKey();
        ArrayList<String> list = //..fetch data method ()
        HashMap<String, String> hmPQdata = //..fetch data method ()

        SendNForgotHelperThread helperThread = new SendNForgotHelperThread(objDataKey, list, hmPQdata);
        Thread t = new Thread(helperThread);
        t.start();
    }

}

class SendNForgotHelperThread implements Runnable {

    private ArrayList<String> list;
    private HashMap<String, String> hmPQdata;
    private DataKey objDataKey;

    public SendNForgotHelperThread(DataKey objDataKey, ArrayList<String> list, HashMap<String, String> hmPQdata) {
        this.list = list;
        this.hmPQdata = hmPQdata;
        this.objDataKey = objDataKey;
    }

    @Override
    public void run() {

        try {

            // Option 1 : synchronized method - SendNForgotHelperThread class object locking

            DataCollector objDataSenderM = new DataCollector();
            objDataSenderM.synchronizedMethodStore(this.objDataKey, this.list, this.hmPQdata);

            // Option 2 : synchronized block - SendNForgotHelperThread class object locking

            synchronized (this) {
                DataCollector objDataSender = new DataCollector();
                objDataSender.store(this.objDataKey, this.list, this.hmPQdata);
            }

            // Option 3 : Class level locking

            synchronized (SendNForgotHelperThread.class) {
                DataCollector objDataSender = new DataCollector();
                objDataSender.store(this.objDataKey, this.list, this.hmPQdata);
            }

        } catch (Exception iex) {
            System.out.println("Exception in thread: " + iex.getMessage());
        }
    }
}

class DataCollector {

    public void store(DataKey objDataKey, ArrayList<String> list, HashMap<String, String> hmPQdata) {

        HashMap<String, String> retrivedValue = (HashMap<String, String>) MemCacheUtil
                .retrieveFromMemCache(objDataKey.getKey());

        retrivedValue.putAll(hmPQdata);

        MemCacheUtil.addToMemCache(objDataKey.getKey(), retrivedValue, "expTime value");

        // Sending data in queue
        sendDataToQueue(objDataKey, list, hmPQdata);

    }

    synchronized void synchronizedMethodStore(DataKey objDataKey, ArrayList<String> list,
            HashMap<String, String> hmPQdata) {
        store(objDataKey, list, hmPQdata);

    }

}

class DataKey {
    private String key;

    public String getKey() {
        return key;
    }

    public void setKey(String key) {
        this.key = key;
    }
}

public void sendDataToQueue(DataKey objDataKey, ArrayList<String> list, HashMap<String, String> hmPQdata) {
    // sending data to queue

}

}

用户1：

public class UserA {

public static void main(String[] args) {
    DataProcessor objDataProcessor = new DataProcessor();
    Thread thProcessorThread = new Thread(objDataProcessor, "PROCESSOR");
    thProcessorThread.start();
}

}

用户2：

public class UserB {

public static void main(String[] args) {
    DataProcessor objDataProcessor = new DataProcessor();
    Thread thProcessorThread = new Thread(objDataProcessor, "PROCESSOR");
    thProcessorThread.start();
}

}

用户A＆amp; B将同时调用DataProcessor线程。很明显，选项1＆amp; 2将面临竞争条件，因为它们是该类/自我类对象锁定的锁定对象，而选项3将在类级别上提供锁定 - 如果多个用户将同时访问该程序，则选项3将减慢应用程序和整个目的多线程将继续折腾。

任何人都可以建议如何处理这种情况。

修改：

任何人都可以帮助处理SendNForgotHelperThread线程对象的竞争条件 - 这个线程是从循环中调用的，并且每个循环都会启动新线程SendNForgotHelperThread。

Answer 1

您正在将DataProcessor的两个不同实例传递给类UserA和UserB中的线程，如果启动这些主要方法，它将正常运行。你的申请中不会出现竞争条件。

要发生竞争条件，你必须传递共享对象，即多个线程对同一个对象进行操作，共享对象应该具有字段/属性以在多个线程之间共享

    DataProcessor objDataProcessor = new DataProcessor();
    Thread thProcessorThread1 = new Thread(objDataProcessor, "PROCESSOR-1");
    thProcessorThread1.start();
    Thread thProcessorThread2 = new Thread(objDataProcessor, "PROCESSOR-2");
    thProcessorThread2.start();

Java线程：多线程 - 竞争条件

1 个答案: