Question

提前谢谢你。我感谢任何反馈。我是编程新手，我正在编写一个根据用户要求的数字打印斐波纳契数列的作业。我有大部分代码完成，但还有一件我遇到困难的部分。我希望我的输出采用表格格式，但是我的代码中有些东西已关闭，而且我没有得到我想要输出的所有数据。灰色是我的代码，输出和我想要的输出。

#include <stdio.h>
#include <stdlib.h>

int main()
{
int i, n;
int sequence = 1;
int a = 0, b = 1, c = 0;

printf("How many Fibonacci numbers would you like to print?: ");
scanf("%d",&n);

printf("\n n\t\t Fibonacci Numbers\n");

printf(" %d \t\t\t%d\n \t\t\t%d\n ", sequence, a, b);

for (i=0; i <= (n - 3); i++)
{
    c = a + b;
    a = b;
    b = c;
    sequence++;
    printf("\t\t\t%d\n ", c);
}
return 0;
}

Here is my output: 
How many Fibonacci numbers would you like to print?: 8

n        Fibonacci Numbers
1           0
            1
            1
            2
            3
            5
            8
            13

Here is my desired output: 
How many Fibonacci numbers would you like to print?: 8

 n       Fibonacci Numbers
 1          0
 2          1
 3          1
 4          2
 5          3
 6          5
 7          8
 8          13

Answer 1

您忘记在for循环中打印sequence。在给出适当数量的sequence之后，在for循环中打印c和\t！

Answer 2

我没有收到所有数据

那是因为您没有在sequence循环的printf()中打印for。
```
printf("\t\t\t%d\n ", c);
```

甚至在for循环之前的^nd号码之前

printf(" %d \t\t\t%d\n \t\t\t%d\n ", sequence, a, b);

尝试对您的代码进行以下更改：

printf(" %d \t\t\t%d\n %d\t\t\t%d\n ", sequence, a, sequence+1, b);

sequence++; //as you've printed 2 values already in above printf

for (i=0; i <= (n - 3); i++)
{
    c = a + b;
    a = b;
    b = c;
    printf("%d\t\t\t%d\n ",++sequence, c); 
 //or do sequence++ before printf as you did and just use sequence in printf
}

示例输入： 5

示例输出：

How many Fibonacci numbers would you like to print?: 5 
 n       Fibonacci Numbers
 1          0
 2          1
 3          1
 4          2
 5          3

编辑：您可以通过这种方式使用功能......这几乎是一样的事情：）

#include <stdio.h>

void fib(int n)
{
    int i,sequence=0,a=0,b=1,c=0;

    printf("\n n\t\t Fibonacci Numbers\n");

    printf(" %d \t\t\t%d\n %d\t\t\t%d\n ", sequence, a, sequence+1, b);

    sequence++;

    for (i=0; i <= (n - 2); i++)
    {
        c = a + b;
        a = b;
        b = c;
        printf("%d\t\t\t%d\n ",++sequence, c);
    }
}

int main()
{
int n;

printf("How many Fibonacci numbers would you like to print?: ");
scanf("%d",&n);
fib(n);

return 0;
}

Answer 3

这样可行，也可以更好地缩进代码：

int main() {
    int i, n;
    int sequence = 1;
    int a = 0, b = 1, c = 0;

    printf("How many Fibonacci numbers would you like to print?: ");
    scanf("%d",&n);

    printf("\n n\t\tFibonacci Numbers\n");

    printf(" %d\t\t\t%d\n", sequence, a);
    printf(" %d\t\t\t%d\n", ++sequence, b); //   <- and you can use pre increment operator like this for your purpose

    for (i=0; i <= (n - 3); i++) {
        c = a + b;
        a = b;
        b = c;
        sequence++;
        printf(" %d\t\t\t%d\n",sequence, c);
    }

    return 0;
}

输出：

How many Fibonacci numbers would you like to print?: 4

 n      Fibonacci Numbers
 1          0
 2          1
 3          1
 4          2

为Fibonacci序列创建表

3 个答案: