Question

如果我有这样的对象：

"names" : 
{
  'name1' : 'Mike',
  'name2' : 'Tom',
..}

"numbers" :
{
  'number1' : 'b1',
  'number2' : 'b2',
..}

"levels" :
{
  'level1' : '0',
  'level2' : '0',
...
}

如何创建三个单独的对象，如：

declare variable $testseq as item()* := ();

declare function local:insertseq($target as item()*, $position as xs:integer?, $inserts as item()*)
as item()* (:might be great if we have a keyword to represent nothing:)
{
  fn:insert-before($target, 1, $inserts) (:change the global sequence:)
  () (:simulate returning nothing, empty sequence:)
};

element test
{
  attribute haha {"&amp;"},
  local:insertseq($testseq, 1, ('a', 'b')),
  $testseq
}

Answer 1

您可以使用键和元素迭代的数量作为属性。

＆＃13;

var myObj = [{ 'name': 'Mike', 'number': 'b1', 'level': 0 }, { 'name': 'Tom', 'number': 'b2', 'level': 0 }],
    result = {};

myObj.forEach(function (a, i) {
    Object.keys(a).forEach(function (k) {
        result[k + 's'] = result[k + 's'] || {};
        result[k + 's'][k + (i + 1)] = a[k];
    });
});

console.log(result);

＆＃13;

Answer 2

使用Object.keys函数，ES6箭头函数表达式和预定义parts对象的替代解决方案：

var myObj = [{'name': 'Mike', 'number': 'b1', 'level': 0},{'name': 'Tom', 'number': 'b2', 'level': 0}],
    parts = {'names': {}, 'numbers': {}, 'levels': {}};

myObj.forEach(function(obj, i){
    Object.keys(obj).forEach((k) => (parts[k +"s"][k +(i+1)] = obj[k]));
});

console.log(JSON.stringify(parts, 0, 4));

输出：

{
    "names": {
        "name1": "Mike",
        "name2": "Tom"
    },
    "numbers": {
        "number1": "b1",
        "number2": "b2"
    },
    "levels": {
        "level1": 0,
        "level2": 0
    }
}

Answer 3

JS objects中的密钥必须为unique。

name : Tom的后续声明会覆盖您之前的声明。

代码：

var newObj = {};
newObj.names = {};
newObj.numbers = {};
newObj.levels = {};

for (var i in myObj) {
newObj.names.name = myObj[i].name;
newObj.numbers.number = myObj[i].number;
newObj.levels.level = myObj[i].level;
}

console.log(newObj);

演示小提琴：https://jsfiddle.net/29pb33dj/

使用索引的正确键更新了答案：

var newObj = {};
newObj.names = {};
newObj.numbers = {};
newObj.levels = {};

for (var i in myObj) {
newObj.names[i] = myObj[i].name;
newObj.numbers[i] = myObj[i].number;
newObj.levels[i] = myObj[i].level;
}

console.log(newObj);

工作演示：https://jsfiddle.net/29pb33dj/1/

将一个对象分成三个部分

3 个答案: