我有一个带有整数列的pandas DataFrame。我想要包含数字大于10的行。我可以通过执行以下操作来评估True或False而不是实际值：
df['ints'] = df['ints'] > 10
我不经常使用Python，因此我会围绕这个问题进行讨论。
我花了20分钟谷歌搜索但未能找到我需要的东西....
修改
observationID recordKey gridReference siteKey siteName featureKey startDate endDate pTaxonVersionKey taxonName authority commonName ints
0 463166539 1767 SM90 NaN NaN 150161 12/02/2006 12/02/2006 NBNSYS0100004720 Pipistrellus pygmaeus (Leach, 1825) Soprano Pipistrelle 2006
1 463166623 4325 TL65 NaN NaN 168651 21/12/2008 21/12/2008 NHMSYS0020001355 Pipistrellus pipistrellus sensu stricto (Schreber, 1774) Common Pipistrelle 2008
2 463166624 4326 TL65 NaN NaN 168651 18/01/2009 18/01/2009 NHMSYS0020001355 Pipistrellus pipistrellus sensu stricto (Schreber, 1774) Common Pipistrelle 2009
3 463166625 4327 TL65 NaN NaN 168651 15/02/2009 15/02/2009 NHMSYS0020001355 Pipistrellus pipistrellus sensu stricto (Schreber, 1774) Common Pipistrelle 2009
4 463166626 4328 TL65 NaN NaN 168651 19/12/2009 19/12/2009 NHMSYS0020001355 Pipistrellus pipistrellus sensu stricto (Schreber, 1774) Common Pipistrelle 2009
答案 0 :(得分：30)
样本DF：
@Override
public void onBindViewHolder(ViewHolder viewHolder, final int position) {
viewHolder.txtViewTitle.setText(itemsData[position].getItem_title());
viewHolder.badge.setImageResource(itemsData[position].getBadge_index());
仅显示In [79]: df = pd.DataFrame(np.random.randint(5, 15, (10, 3)), columns=list('abc'))
In [80]: df
Out[80]:
a b c
0 6 11 11
1 14 7 8
2 13 5 11
3 13 7 11
4 13 5 9
5 5 11 9
6 9 8 6
7 5 11 10
8 8 10 14
9 7 14 13
b > 10满足In [81]: df[df.b > 10]
Out[81]:
a b c
0 6 11 11
5 5 11 9
7 5 11 10
9 7 14 13
条件
b > 10满足In [82]: df[df.b > 10].min()
Out[82]:
a 5
b 11
c 9
dtype: int32
条件
b列）
b > 10更新：从Pandas 0.20.1 the .ix indexer is deprecated, in favor of the more strict .iloc and .loc indexers开始。