将数据发送到服务类中的服务器

时间:2016-06-11 05:14:54

标签: java android service httpurlconnection

我正在尝试在用户移动互联网变为活动状态时向服务器发送数据,在我的应用程序中,只要互联网连接处于活动状态,我的广播接收器就会调用服 以下是方法。我尝试post和get方法,但它不向网站请求。我无法打印"我正在服务5"(下面我已打印)。它不会更新我的数据库。

public class LocalService extends Service
{
....
....
public void sendfeedback(){



        System.out.println("i am in service4");
        String filename =MainScreenActivity.UserName;


        HttpURLConnection urlConnection = null;
        final String target_uri =
                "http://readoline.com/feedback.php";






        try {
            BufferedReader mReader = new BufferedReader(new InputStreamReader(getApplicationContext().openFileInput(filename)));
            String line;
            StringBuffer buffer = new StringBuffer();


            while ((line = mReader.readLine()) != null) {
                buffer.append(line + "\n");
            }
            System.out.println(buffer.toString());


            try {
                System.out.println("i am in service41"+buffer.toString());
                Uri buildUri = Uri.parse("http://readoline.com/feedback.php" + "?").buildUpon()
                        .appendQueryParameter("user_id", filename)
                        .appendQueryParameter("feedback", buffer.toString())
                        .build();

                URL url = new URL(buildUri.toString());



                urlConnection = (HttpURLConnection) url.openConnection();
                urlConnection.setRequestMethod("GET");
                urlConnection.connect();

                System.out.println("i am in service44");
            /*  PrintWriter out=new PrintWriter(urlConnection.getOutputStream());
                out.write("user_id="+filename);
                out.write("&");
                out.write("feedback="+buffer.toString());
            */
                    System.out.println("i am in service5");


                //  Log.e(LOG_TAG,dataToSend.toString());


                //out.close();
                // Read the input stream into a String


            }catch (IOException e){
                System.out.println("i am in service6");
                e.printStackTrace();
            }finally {
                if (urlConnection!=null){
                    urlConnection.disconnect();
                }
            }



        }catch(Exception e){

        }
    }
}

0 个答案:

没有答案