当我不使用memcopy时,我的程序是一个OpenGL程序编译并运行正常,但是当在程序中使用此函数时,当我尝试在编译后运行程序时它会给我一个seg错误,它仍然在两个程序中编译但是当我用这个函数编译程序时给了我seg错误,并且在gdb中检查时的seg错误没有显示memcpy作为问题,而是初始化函数init()为我创建了opengl上下文,但奇怪的是只有当我在程序中包含memcpy并编译它时才会发生这种情况,否则init()工作正常,我也在另一个文件中测试它以确认它是否可以自行运行
我不知道为什么会这样做,我注意到这已经发生了,因为linux mint升级了一些软件包,程序在升级之前工作正常
这是程序源代码
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <X11/Xlib.h>
#include <X11/Xutil.h>
#include <GL/glew.h>
#include <GL/glx.h>
#include <time.h>
#include <math.h>
#include "glx2.c"
#include "renderBuffer.h"
#include "new.hpp"
#define WIDTH 1080
#define HEIGHT 720
int main(){
init(WIDTH,HEIGHT);
createShaders();
char name[1][25];
float returned[720][1080][2] = {0.0f};
strcpy(name[0],"ryu2.bmp");
GLuint frameBuffer = createFramebuffer(frameBuffer);
GLuint renderTexture = createRenderTexture(renderTexture, WIDTH,HEIGHT);
//GLuint depth_texture;
//glGenTextures(1, &depth_texture);
//glBindTexture(GL_TEXTURE_2D, depth_texture);
//glTexStorage2D(GL_TEXTURE_2D, 1, GL_DEPTH_COMPONENT32F, 1080, 720);
//glFramebufferTexture(GL_FRAMEBUFFER,GL_DEPTH_ATTACHMENT,depth_texture, 0);
glFramebufferTexture(GL_FRAMEBUFFER,GL_COLOR_ATTACHMENT0,renderTexture,0);
static const GLenum draw_buffers[] = { GL_COLOR_ATTACHMENT0 };
glDrawBuffers(1, draw_buffers);
//bind framebuffer
glBindFramebuffer(GL_FRAMEBUFFER,frameBuffer);
checkFramebuffer();
GLfloat vertices[] = {
//
// X Y U V
//triangle 1
-1.0, -1.0, 0.0, 0.0,
-22.0/27.0, -1.0, 100.0/800.0, 0.0,
-1.0, -41.0/60.0, 0.0, 114.0/342.0,
-22.0/27.0, -41.0/60.0, 100.0/800.0, 114.0/342.0};
GLuint vao1 = createVao();
GLuint vbo1 = createVbo();
glBufferData(GL_ARRAY_BUFFER, sizeof(vertices), vertices, GL_STATIC_DRAW);
GLuint tex = createTexture(name[0]);
//set up data format in opengl and save in vao
glVertexAttribPointer(0, 2, GL_FLOAT, GL_FALSE, 4*sizeof(GLfloat), 0);
glEnableVertexAttribArray(0);
glVertexAttribPointer(1, 2, GL_FLOAT, GL_FALSE, 4*sizeof(GLfloat), (const GLvoid*)(2 * sizeof(GLfloat)));
glEnableVertexAttribArray(1);
bindObject(vao1, tex);
glBindFramebuffer(GL_FRAMEBUFFER, frameBuffer);
glViewport(0,0, WIDTH,HEIGHT);
glDrawArrays(GL_TRIANGLE_STRIP, 0, 4);
//////completed drawing to framebuffer original values
glBindFramebuffer(GL_FRAMEBUFFER,0);
glBindTexture(GL_TEXTURE_2D, renderTexture);
glGetTexImage(GL_TEXTURE_2D, 0,GL_RG,GL_FLOAT,(void *)&returned);
float another[720][1080][2];
memcpy((void *)another, (const void *)returned, sizeof(returned));
//----------------------completed copying original values to array for all comparison
int i = 0,j=0;
//for(j=0; j<114;j++)
// for(i=0; i<100;i++){
//printf("%f %f\n",another[j][i][0], another[j][i][1]);
//}
//from this point on there will be change and comparison
//GLuint disp = glGetUniformLocation(shader_program, "disp");
//glUniform2f(disp, 1.0/540,1.0/360);
glXMakeCurrent( dpy, 0, 0 );
glXDestroyContext( dpy, ctx );
glXDestroyWindow(dpy, glxWin);
XDestroyWindow( dpy, win );
XFreeColormap( dpy, cmap );
XCloseDisplay( dpy );
return 0;
}
当我运行gdb这是它给出的问题,尽管当我评论memcpy它工作正常并没有给我任何seg错误
Program received signal SIGSEGV, Segmentation fault.
0x0000000000402876 in main () at untitled.cpp:22
22 init(WIDTH,HEIGHT);
(gdb)
答案 0 :(得分:3)
@BarmakShemirani指出的答案是linux的堆栈限制为8mb,因为这两个数组总共超过12mb因此会覆盖堆栈,因此为什么会出现问题,解决方法是写入/使用malloc()
分配给堆答案 1 :(得分:-1)
@BarmakShemirani关于堆栈限制是正确的。您还可以使用代码中的setrlimit.来增加堆栈限制(但最好不要在main function中)。