我有一个使用argparse
的python脚本。在命令行上键入python script_name.py -h
后,它会显示另一个命令的帮助消息,但代码仍然有效。该脚本可以识别其中定义的选项并运行良好。看起来脚本是由某种东西打包的。我把argparse
放在一个函数中,一切都很好。我只是无法找出导致帮助消息发生变化的原因。
以下是代码:
#!/usr/bin/env python
import os
import sys
import json
import logging
import argparse
import handlers
HZZ_DIR = os.path.dirname(os.path.abspath(__file__))
ROOT_DIR = os.path.dirname(os.path.dirname(HZZ_DIR))
logger = logging.getLogger('hzz_logger')
logger.setLevel(logging.DEBUG)
console = logging.StreamHandler()
console.setLevel(logging.INFO)
logger.addHandler(console)
def parse_args():
arg_parser = argparse.ArgumentParser()
arg_parser.add_argument('job', choices=['ws','lm','np'],
help="ws: workspace; lm: limit; np: npranking")
arg_parser.add_argument('-a', '--action', nargs=1,
help="for Limit and NPranking: get/plot (limit/pull)")
arg_parser.add_argument('-b', '--blinded', action='store_true',
help="for Limit: true -- do expected only, false -- do observed as well.")
arg_parser.add_argument('-v', '--version', nargs=1, type=int,
help="input version")
arg_parser.add_argument('-t', '--tag', nargs=1,
help='workspace tag')
arg_parser.add_argument('-m', '--mass', nargs='+', type=int,
help='signal mass(es)')
arg_parser.add_argument('-c', '--config', nargs=1,
help='configure file')
arg_parser.add_argument('-u', '--update', action='store_true',
help="update default settings")
args = arg_parser.parse_args()
return args
def load_settings(args):
pass
def run_job(settings):
pass
def execute():
args = parse_args()
settings = load_settings(args)
run_job(settings)
if __name__ == '__main__':
execute()
此处粘贴了帮助消息,这实际上是在此代码中未直接使用的命令的帮助消息。也可以识别此命令的选项......
$ python hzz_handler.py -h
Usage: python [-l] [-b] [-n] [-q] [dir] [[file:]data.root] [file1.C ... fileN.C]
Options:
-b : run in batch mode without graphics
-x : exit on exception
-n : do not execute logon and logoff macros as specified in .rootrc
-q : exit after processing command line macro files
-l : do not show splash screen
dir : if dir is a valid directory cd to it before executing
-? : print usage
-h : print usage
--help : print usage
-config : print ./configure options
-memstat : run with memory usage monitoring
答案 0 :(得分:0)
哇,另一个反Python根源之谜!您的问题和评论确实很有帮助。为什么没有人用ROOT.PyConfig.IgnoreCommandLineOptions = True
发布答案?
这是一个原始的解决方法:
import argparse
# notice! ROOT takes over argv and prints its own help message when called from command line!
# instead I want the help message for my script
# therefore, check first if you are running from the command line
# and setup the argparser before ROOT cuts in
if __name__ == '__main__':
parser = argparse.ArgumentParser(
formatter_class = argparse.RawDescriptionHelpFormatter,
description = "my script",
epilog = "Example:\n$ python my_script.py -h"
)
parser.add_argument("param", type=str, help="a parameter")
parser.add_argument("-d", "--debug", action='store_true', help="DEBUG level of logging")
args = parser.parse_args()
if args.debug:
logging.basicConfig(level=logging.DEBUG)
else:
logging.basicConfig(level=logging.INFO)
logging.debug("parsed args: %s" % repr(args))
import ROOT
...
if __name__ == '__main__':
<do something with args>
答案 1 :(得分:0)
在排序中,答案是始终在 argparse 之后调用 import ROOT
。然后 ROOT 不会接管 argparse 并打印我们想要的所需消息。