将可拖动DIV的位置存储到MySQL数据库

时间:2016-06-10 07:37:49

标签: javascript html5 css3

我想知道是否/如何能够存储我在屏幕上移动可拖动div的位置,以便在重新加载页面时,它将返回到它被留下的时间。

代码在这里

function drag_start(event) {
    var style = window.getComputedStyle(event.target, null);
    event.dataTransfer.setData("text/plain",
    (parseInt(style.getPropertyValue("left"),10) - event.clientX) + ',' + (parseInt(style.getPropertyValue("top"),10) - event.clientY));
} 
function drag_over(event) { 
    event.preventDefault(); 
    return false; 
} 
function drop(event) { 
    var offset = event.dataTransfer.getData("text/plain").split(',');
    var dm = document.getElementById('dragme');
    dm.style.left = (event.clientX + parseInt(offset[0],10)) + 'px';
    dm.style.top = (event.clientY + parseInt(offset[1],10)) + 'px';
    event.preventDefault();
    return false;
} 
var dm = document.getElementById('dragme'); 
dm.addEventListener('dragstart',drag_start,false); 
document.body.addEventListener('dragover',drag_over,false); 
document.body.addEventListener('drop',drop,false); 
aside { 
    position:  absolute;
    left: 0;
    top: 0; /* set these so Chrome doesn't return 'auto' from getComputedStyle */
    width: 200px; 
    background: rgba(255,255,255,0.66); 
    border: 2px  solid rgba(0,0,0,0.5); 
    border-radius: 4px; padding: 8px;
}
<aside draggable="true" id="dragme">
    This is an aside, drag me.
</aside>
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2 个答案:

答案 0 :(得分:1)

无论您需要存储在数据库中,都必须使用Ajax与将与数据库交互的服务器(例如Web服务器上的PhP脚本)进行通信。 JavaScript本身不能与数据库交互。

在这里,您可以找到关于Ajax的W3C页面:http://www.w3schools.com/ajax/

注意IE等浏览器上的不同方法,有些版本严重支持作为Ajax基础对象的XmlHttpRequest对象。

在您的情况下,根据您要执行的操作,您只能存储div的位置,然后在页面加载时检索数据库的位置。另一个解决方案,我认为更脏,是将整个HTML页面保存在数据库中。 Ajax能够发送和带回几种类型的数据,例如JSON,原始文本,XML,以及可以在div或其他任何内容中注入的即用型HTML。

希望有所帮助

编辑:请注意,如果要将大量数据发送到服务器,则必须使用POST方法,而不是GET方法,该方法不受大小限制。 GET只能发送div的位置,但如果发送整页则需要POST。 See here了解更多详情。

答案 1 :(得分:1)

您真的想将其存储在数据库中吗?用户可以拥有许多设备,您的站点布局(以及div的位置)因此不同。

考虑将其存储在本地存储或Cookie(your example)中。

var pos = {left: dm.style.left, top: dm.style.top};
document.cookie = JSON.stringify(pos);
try {
    var pos = JSON.parse(document.cookie);
    dm.style.left = pos.left ? pos.left : '0px';
    dm.style.top = pos.top ? pos.top : '0px';
} catch (e) {
    // Some error handling
}