Question

我使用以下python代码

获取JIRA数据

如何存储多个密钥的响应（我的示例只显示一个KEY，但通常我会获得大量数据）并打印仅与total,key, customfield_12830, summary <对应的值< / p>

    import requests
    import json
    import logging
    import datetime
    import base64
    import urllib
    serverURL = 'https://jira-stability-tools.company.com/jira'
    user = 'username'
    password = 'password'
    query = 'project = PROJECTNAME AND "Build Info" ~ BUILDNAME  AND assignee=ASSIGNEENAME'
    jql = '/rest/api/2/search?jql=%s' % urllib.quote(query)
    response = requests.get(serverURL + jql,verify=False,auth=(user, password))
    print response.json()

response.json()输出： -

http://pastebin.com/h8R4QMgB

Answer 1

从您粘贴到pastebin的链接和我看到的json，您的issues列表包含key, fields(which holds custom fields), self, id, expand。

您可以简单地遍历此响应并提取所需键的值。你可以去。

data = response.json()
issues = data.get('issues', list())

x = list()

for issue in issues:
    temp = {
        'key': issue['key'],
        'customfield': issue['fields']['customfield_12830'],
        'total': issue['fields']['progress']['total']
    }
    x.append(temp)
print(x)

x 是包含您提到的字段数据的字典列表。如果我某处不清楚或者我所提供的内容不是您想要的，请告诉我。

PS：始终建议您使用 dict.get（＆＃39; keyname＆＃39;，无）来获取值，因为您始终可以设置默认值如果找不到密钥，则为value。对于这个解决方案，我没有这样做，因为我只想提供方法。

更新：在您（OP）提到的评论中，它给出了attributerror.Try this code

data = response.json()
issues = data.get('issues', list())

x = list()

for issue in issues:
    temp = dict()
    key = issue.get('key', None)
    if key:
       temp['key'] = key 

    fields = issue.get('fields', None)
    if fields:
        customfield = fields.get('customfield_12830', None)
        temp['customfield'] = customfield

        progress = fields.get('progress', None)
        if progress:
            total = progress.get('total', None)
            temp['total'] = total

    x.append(temp)
print(x)

从Python中的JSON文件中选择值

1 个答案: