Question

我试图通过解析HAR文件来获取每个页面的总加载时间。我找到了一个代码段，通过从页面开头减去最后一次获取的时间来找到总时间。到目前为止一切都很好。

我有一个遍历所有页面的外部循环。

      List<HarPage> pages = log.getPages().getPages();
        for (HarPage page : pages)
        {
        / confirms that I go through all the pages
        writer.println("\n\n***\n    Top of page loop, Page Number   :" + pageNumber);
        }



/* The problem is that I would like to process all the entries for one page  at a time.  This inner loop is not working properly and seems to go through  the entries for all the pages.  The calling sequence is as follows:
*/    
    List<HarPage> pages = log.getPages().getPages();
    for (HarPage page : pages)
    {
                        HarEntries entries = log.getEntries();
                        List<HarEntry> entryList = entries.getEntries();
                        int entryIndex = 0;
                        for (HarEntry entry : entryList) {
                        / print entry number to see how many entries it processes
                        writer.println("Page Number: " + pageNumber + "  Entry: " + entryIndex++);
                        entryIndex++;
                        }
    }

我在第一页中有124个条目（我通过http://www.softwareishard.com/har/viewer/处理文件确认了该条目，但我的程序将遍历所有页面的1305个条目。

谢谢，塔里克巴德莎

PS我发现Entry entry.getPageRef（）中有一个字段。当我转到下一页时，这会发生变化。所以也许这可以用作退出内循环的触发器。如果有人有更优雅的解决方案请评论 TB

处理HAR文件时，需要一次获取一页的条目

0 个答案: