找出我已经遇到的球员

时间:2016-06-10 00:32:29

标签: c# data-modeling

我有以下数据结构:

public class Match
{

    public List<Player> Participants;

}

public class Player
{

    public string Name;

}

现在我得到了以下示例数据:

Match 1
 - PlayerA
 - PlayerB
 - PlayerC

Match 2
 - PlayerA
 - PlayerB
 - PlayerD
 - PlayerE

根据这些数据,如果PlayerA想知道他玩哪些球员,答案是PlayerB, PlayerC, PlayerD and PlayerE

现在我的问题是,如果我想要显示哪个玩家与谁一起玩多久,那么这将是最具逻辑性和易于查询的数据结构。毕竟我想向用户展示一个这样的图表(超级油漆技能):

Chart

2 个答案:

答案 0 :(得分:2)

作为使您的解决方案更整洁的建议,让Player覆盖等于。代码如下所示:

public class Player
{
    public override bool Equals(object obj)
    {
        var other = obj as Player;
        if (other == null)
            return false;
        return this.Name == other.Name;
    }

    public override int GetHashCode()
    {
        return this.Name.GetHashCode();
    }

    public string Name;
}

这使你可以按照这个

的方式制作一个更易读的对手寻找解决方案
Player me = new Player { Name = "Me" };
var allMatches = new List<Match>
{
    new Match
    {
        Participants = new List<Player> 
        {
            me,
            new Player { Name = "Some Other Dude"}
        }
    },

    new Match
    {
        Participants = new List<Player>
        {
            me,
            new Player { Name = "My Rival" }
        }
    }
};

var myMatches = allMatches.Where(m => m.Participants.Contains(me)).ToList();
var myOpponents = myMatches.SelectMany(m => m.Participants.Except(new [] {me})).Distinct();

答案 1 :(得分:0)

您可以使用Linq

执行此操作
List<List<Match> matches = ...
string player = "playerA";

var coplayers = matches.Where(x=>x.Any(p=>p.Participants.Any(s=>s.Name == player))) // get all participants where group contains participant.
           .SelectMany(x=> x.SelectMany(p=>p.Participants))                         // get all participants where group contains participant.
           .Where(x=>x.Name != player)                                              // List co participants 
           .GroupBy(x=>x.Name)                                                      // Distinct by grouping on Name or( need to override equal)
           .Select(x=>x.FirstOrDefault())
           .ToList()    

选中此Demo