我们可以根据输入值获取compareOperator值吗?例如,如果我的输入是 eq ,那么它应该选择CompareFilter.CompareOp.EQUAL
,否则如果输入是 ne ,它应该选择CompareFilter.CompareOp.NOT_EQUAL
。
像
这样的东西if(input.equals("eq")) {
myCompareOp = EQUAL;
}else if(input.equals("ne")) {
myCompareOp = NOT_EQUAL;
}
SingleColumnValueFilter colValFilter = new SingleColumnValueFilter(Bytes.toBytes(<CF>), Bytes.toBytes(<CQ>)
, myCompareOp, new BinaryComparator(Bytes.toBytes(<value>)));
任何建议都将受到赞赏
答案 0 :(得分:1)
根据以上代码,是的,它会起作用。下面是示例代码片段,您也可以查看。其中ConditionType
是枚举...这样您也可以准备自己的枚举(如果条件也很好,则不是必需的)
private Filter buildSimpleQuery(ConditionType ct, String name, Object value) {
name = super.getRealPropertyName(name);
validatePropertyValue(name, value);
Class<?> clazz = getPrimitiveFieldClass(name, value.getClass());
CompareOp compareOp = null;
boolean regexCompRequired = false;
switch (ct) {
case EQUALS:
compareOp = CompareOp.EQUAL;
regexCompRequired = String.class == clazz && value.toString().endsWith("*");
break;
case NOT_EQUALS:
compareOp = CompareOp.NOT_EQUAL;
regexCompRequired = String.class == clazz && value.toString().endsWith("*");
break;
case GREATER_THAN:
compareOp = CompareOp.GREATER;
break;
case GREATER_OR_EQUALS:
compareOp = CompareOp.GREATER_OR_EQUAL;
break;
case LESS_THAN:
compareOp = CompareOp.LESS;
break;
case LESS_OR_EQUALS:
compareOp = CompareOp.LESS_OR_EQUAL;
break;
default:
break;
}
String qualifier = name;
String theFamily = family != null ? family : familyMap.get(qualifier);
ByteArrayComparable byteArrayComparable = regexCompRequired
? new RegexStringComparator(value.toString().replace("*", "."))
: new BinaryComparator(value.toString().getBytes(StandardCharsets.UTF_8));
Filter query = new SingleColumnValueFilter(theFamily.getBytes(StandardCharsets.UTF_8),
qualifier.getBytes(StandardCharsets.UTF_8),
compareOp,
byteArrayComparable);
return query;
}