Question

以下是我的C代码。我不知道为什么数组mins（以及meds和maxs）中索引0处的值在最后一次循环迭代中发生了变化。请帮忙。

很抱歉添加了太多的打印声明。这些主要用于调试。

#include<stdio.h>
#include<stdlib.h>
#define SZ 10000

typedef long long LL;


LL min(LL x, LL y)
{
    return x<y?x:y;
}

LL max(LL x, LL y)
{
    return x>y?x:y;
}

struct triangle
{
    LL sm, md, lg;
};

int main()
{
    int n, i, ans;
    struct triangle obj[n];
    LL mins[n], meds[n], maxs[n];
    LL a, b, c;
    scanf("%d%*c", &n);
    for(i=0;i<n;i++)
    {
        scanf("%lld%lld%lld%*c", &a, &b, &c);
        printf("Scanned : %lld%lld%lld\n", a, b, c);
        obj[i].sm = mins[i] = min(a, min(b,c));
        obj[i].lg = maxs[i] = max(a, max(b, c));
        obj[i].md = meds[i] = max(min(a,b), min(max(a,b),c));
        printf("min : %lld\t med = %lld\t max = %lld\n", mins[i], meds[i], maxs[i]);
        printf("min[0] = %lld\n", mins[0]);
    }

    printf("Outside : min[0] = %lld\n", mins[0]);
    printf("mins : ");
    for(i=0;i<n;i++)
        printf("%lld ", mins[i]);
    printf("\n");
    printf("meds : ");
    for(i=0;i<n;i++)
        printf("%lld ", meds[i]);
    printf("\n");
    printf("maxs : ");
    for(i=0;i<n;i++)
        printf("%lld ", maxs[i]);
    printf("\n");

    //printf("%d\n", ans);
    return 0;
}

Answer 1

您使用未初始化且不确定的n来确定数组的大小。在阅读n之后声明数组：

int main()
{
    int n, i, ans;
    LL a, b, c;
    if(scanf("%d%*c", &n) != 1) {
        fputs("failed to read n\n", stderr);
        return 1;
    }
    struct triangle obj[n];
    LL mins[n], meds[n], maxs[n];

索引0处的数组值在C中循环结束时更改

1 个答案: