Question

我正在用nightwatch运行这个测试，我在循环中有一个循环，第一个运行正常，但它无法进入第二个循环。我写了一个console.log并返回：

Number of links:[object Object]

这是我的代码：不进入循环2的原因是什么？提前谢谢。

 .execute(
            function() {
                return document.querySelectorAll('.menuElementsAgregator>li').length
            },
            function(result) {
                total_links = result.value;
                console.log("Number of main links:" + total_links);
                for (var i = 2; i <= total_links; i++) {
                  (function (i) {
                      browser.waitForElementPresent('.menuElementsAgregator', 3000)
                             .click('.menuElementsAgregator>li:nth-child(' + i + ')>a')
                             .waitForElementVisible('.menuElementsAgregator>li:nth-child(' + i + ')', 2000)
                        .execute(
                                function () {
                                    return document.querySelectorAll('.menuElementsAgregator>li:nth-of-type(' + i + ')>.tsr-nav-second-level .has-sub .clickableTabWithLink').length
                                },
                                    function(result) {
                                    total_links2 = result.value;
                                    console.log("Number of links:" + total_links2);
                                for (var j = 2; j <= total_links2 + 1; j++) {
                                    browser.waitUntilElementIsClickable('.menuElementsAgregator>li:nth-child(' + i + ')')
                                           .click('.menuElementsAgregator>li:nth-child(' + i + ')')
                                           .waitForElementPresent('.menuElementsAgregator>li:nth-of-type(' + i + ')>.tsr-nav-second-level>li:nth-of-type(' + j + ').has-sub', 5000)
                                           .click(' .menuElementsAgregator>li:nth-of-type(' + i + ')>.tsr-nav-second-level>li:nth-of-type(' + j + ').has-sub  .clickableTabWithLink:first-child')
                                           .pause(1000)
                                           .waitForElementVisible('.games-list', 5000);
                                                                                                         }
                                }
                            )
                  })(i);
              }
          })

Answer 1

问题是total_links不是整数而是对象。

尝试替换

console.log("Number of main links:"+ total_links);

与

console.log("Number of main links:", total_links);

这将显示你在total_links中的内容。如果您无法修复，请添加内容为total_links

的评论

Answer 2

这个代码绝对不行，因为你不能在循环中使用回调，你的索引'i'在第二个循环中总是等于'total_links.length'。你可以试试这个：

        .execute(
      function() {
        return document.querySelectorAll('.menuElementsAgregator>li').length
      },
      function(result) {
        total_links = result.value;
        console.log("Number of main links:" + total_links);
        for (var i = 2; i <= total_links; i++) {
         (function(i){ // this is a closure
          browser.waitForElementPresent('.menuElementsAgregator', 3000)
            .click('.menuElementsAgregator>li:nth-child(' + i + ')>a')
            .waitForElementVisible('.menuElementsAgregator>li:nth-child(' + i + ')', 2000)
            .execute(
              function() {
                return document.querySelectorAll('.menuElementsAgregator>li:nth-child(' + i + ')>.tsr-nav-second-level>.has-sub').length
              },
              function(result2) {
                total_links2 = result2.value;
                console.log("Number of links:" + total_links2);
                for (var j = 0; j <= total_links2; j++) {// i = total_link.length already, before get in to this loop.
                  browser.waitForElementPresent('.menuElementsAgregator>li:nth-child(' + i + ')>.tsr-nav-second-level>.has-sub:nth(' + j + ')', 3000) 
                    .click('.menuElementsAgregator>li:nth-child(' + i + ')>.tsr-nav-second-level>.has-sub:nth(' + j + ')>a')
                    .pause(3000)
                    .waitForElementVisible('.games-list', 5000);
                }
              }
            )
            })(i) // close
        }
      }
    )

你应该看看api .perform（），这对这类工作有很大的帮助。它使我的代码更清晰，更易读。 Ps：花一些时间研究关闭。

第二个循环不起作用

2 个答案: