Question

from flask import *
from flask_restful import *
import sqlite3
import database


@app.route('/admin')
def admin():
    """ hanldes the admin page for user entry """

    db = database.database()
    db.create()
    db.table('admin')
    #data = db.print_database('admin')
    #return render_template ("mylogin.html", input = 'admin', dbs = data.fetchall())
    return render_template ("mylogin.html", input = 'admin')

@app.route('/admin', methods = ["POST"])
def admin_post():
    """ hanldes the admin page for user entry """
    print "handling post"
    return request.form['text']

if __name__ == "__main__":
    app.run(debug=True)

HTML代码：我没有在这里发布整个代码，因为没有偏离我面临的问题。我能够打开/ admin页面，当我提供输入时，会收到错误＆＃34;方法不允许所请求的URL＆＃34;

<h2>welcome admin</h2>
<form action="." method ="POST">
    hello admin
    <input type = "text" name = "text">
    <input type = "submit" name ="my-form" value = "Send">
</form>

Answer 1

将您的HTML更改为：

<h2>welcome admin</h2>
<form action="{{ url_for('admin_post') }}" method ="POST">
   <input type = "text" name = "text">
   <input type = "submit" name ="my-form" value = "Send">
</form>

您基本上将表单发送到仅接受 GET 请求的 admin 功能。

您需要将表单发布到接受 POST 请求的 admin_post 功能。

请求的URL不允许使用方法

1 个答案: