Question

这个问题已被多次询问过。但我得到了一个共同的答案，即通过response.getwriter().write("....")内部servlet发送响应。但这不是通过ajax发送响应的实际方式。我想通过响应更新<div>而不是整页。但我没有找到解决方案。我的代码如下： -

的index.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<script src="jquery.js" ></script>
<form name="myForm" method="post" id="search" action="al">
<input type="text" name="fname"/>
<input type="submit" value="Search" id="button1"/>
</form>

<div id="some">

</div>
<script>
$("#myForm").submit(function(e)
        {
            var postData = $(this).serializeArray();
            var formURL = $(this).attr("action");
            $.ajax(
            {
                url : formURL,
                type: "POST",
                data : postData,
                success:function(response) 
                {
                $("#some").text(response);
                    //console.log(response);
                    //data: return data from server
                },
                error: function(response) 
                {
                    //if fails      
                }
            });e.preventDefault();});


});
</script>


</body>
</html>

AddressLocator.java

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        // TODO Auto-generated method stub
        String name=request.getParameter("fname");
        //response.getWriter().println("abc.html");
        //response.sendRedirect("getData");
        URL oracle = new URL("https://maps.googleapis.com/maps/api/geocode/json?address="+name);
        URLConnection yc = oracle.openConnection();
        BufferedReader in = new BufferedReader(new InputStreamReader(
                                yc.getInputStream()));
        String inputLine;
        while ((inputLine = in.readLine()) != null) 
            response.getWriter().write(inputLine);
        in.close();

    }

这里，al映射到AddressLocator类。请提前帮助... thanx ..

如何通过ajax从servlet发送响应回jsp？

0 个答案: