Question

这实际上是我在这里发表的第一篇文章。可能是分号问题，但我会试一试，因为我的headeache比埃菲尔铁塔大。

所以我在我的网站上添加了一个联系表单，但是它有问题，因为它正在发送电子邮件，但是当我收到它时它是空的。它只显示PHP文件中的文本（名称：，电子邮件：等），但没有来自输入表单的提示。

代码如下所示：的 HTML

    <div class="contact-form bottom">
                    <h2>Send a message</h2>
                    <form id="main-contact-form" name="contact-form" method="post" action="sendemail.php">
                        <div class="form-group">
                            <input type="text" name="name" class="form-control" required="required" placeholder="Name">
                        </div>
                        <div class="form-group">
                            <input type="email" name="email" class="form-control" required="required" placeholder="Email Id">
                        </div>
                        <div class="form-group">
                            <textarea name="message" required class="form-control" rows="8" placeholder="Your text here"></textarea>
                        </div>                        
                        <div class="form-group">
                            <input type="submit" name="submit" class="btn btn-submit" value="Submit">
                        </div>
                    </form>
                </div>

PHP ：

       <?php

header('Content-type: application/json');

$status = array(

'type'=>'success',

'message'=>'Thank you for contact us. As early as possible  we will contact you '

);


    $name = @trim(stripslashes($_POST['name'])); 

    $email = @trim(stripslashes($_POST['email']));  

    $message = @trim(stripslashes($_POST['message'])); 


    $email_from = $email;

    $email_to = 'a.truta@icloud.com';//replace with your email


    $body = 'Name: ' . $name . "\n\n" . 'Email: ' . $email . "\n\n" . 'Message: ' . $message;


    $success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');


    echo json_encode($status);

    die;

请帮助，我在这里疯了！

Answer 1

正如Marc所说，你应该在表格上做一些验证。这是我很快就会为你敲门的东西。它并不完美，我没有机会测试它，但它会给你一个更好的表格处理起点。不确定json_encode在您的代码中的相关性。

<?php

$toemail = "you@email.address";

if (isset($_POST)) {
    $errors = [];

    // Validate name
    if ((isset($_POST['name'])) and (preg_match("/^[a-zA-Z ]+$/", $_POST['name']))) {
        $name = $_POST['name'];
    } else {
        $errors[] = "Name is invalid";
    }

    // Validate email
    if ((isset($_POST['email'])) and (filter_var($email, FILTER_VALIDATE_EMAIL))) {
        $email = $_POST['email'];
    } else {
        $errors[] = "The email is invalid";
    }

    // Validate message
    if ((isset($_POST['message'])) and (preg_match("/^[0-9a-zA-Z _-]+$/", $_POST['message']))) {
        $message = $_POST['message'];
    } else {
        $errors[] = "The message is invalid";
    }

    if ((isset($name)) and (isset($email)) and (isset($message)) {
        $headers = "MIME-Version: 1.0" . "\r\n";
        $headers .= "Content-type:text/html;charset=UTF-8" . "\r\n";
        $headers .= 'From: <' . $email . '>' . "\r\n";
        if(@mail($toemail, 'New contact form email', $message, $headers)) {
            echo "<p>Mail Sent Successfully</p>\n";
        } else {
            echo "<p>Mail Not Sent Successfully</p>\n";
        }
    } else {
        echo "<p>Form validation has failed</p>";
        foreach ($errors as $error) {
            echo "<p>" . $error . "</p>\n";
        }
    }
} 

?>

Answer 2

嗯，显然问题出在JS文件中。如果没有此代码，电子邮件将准确到达其发送方式，包含内容和内容。所有

JS文件：

    var form = $('#main-contact-form');
form.submit(function(event){
    event.preventDefault();
    var form_status = $('<div class="form_status"></div>');
    $.ajax({
        url: $(this).attr('action'),
        beforeSend: function(){
            form.prepend( form_status.html('<p><i class="fa fa-spinner fa-spin"></i> Email is sending...</p>').fadeIn() );
        }
    }).done(function(data){
        form_status.html('<p class="text-success">Thank you for contact us. As early as possible  we will contact you</p>').delay(3000).fadeOut();
    });
});

联系表单不会显示内容

2 个答案: