Question

在我的网站上，有一个名为＆＃34; My Ideal plank。＆＃34;

这是一个表单，用户将输入他们的数据，并且会有一个返回消息，其中包含该人的理想董事会类型。

第一步，制作表格：完成;

现在我需要连接并注册数据库中的数据。我在Wordpress数据库中创建了一个名为＆＃34; minhaprancha＆＃34;的表。但是我无法在其上记录数据：confused：

连接代码和注册如下：

container.RegisterType<IUnitOfWorkAsync, UnitOfWork>(
            "test",
            new TransientLifetimeManager(),
            new InjectionConstructor(container.Resolve<IDataContextAsync>("test")));

container.RegisterType<ICodeRepository, CodeRepository>();
container.RegisterType<CodesController, CodesController>();

首先，如何在数据库中连接和注册数据？

-----------------------更新---------------------

我管理了它！我直接建立了联系：

JSON
exceptionMessage=An error occurred when trying to create a controller of type 'CodesController'. Make sure that the controller has a parameterless public constructor.
exceptionType=System.InvalidOperationException
innerException
exceptionMessage=Type '<Namespace>.Api.Controllers.CodesController' does not have a default constructor
stackTrace= at System.Linq.Expressions.Expression.New(Type type)
at System.Web.Http.Internal.TypeActivator.Create[TBase](Type instanceType)at System.Web.Http.Dispatcher.DefaultHttpControllerActivator.GetInstanceOrActivator(HttpRequestMessage request, Type controllerType, Func`1& activator)
at System.Web.Http.Dispatcher.DefaultHttpControllerActivator.Create(HttpRequestMessage request, HttpControllerDescriptor controllerDescriptor, Type controllerType)

数据库中插入的代码是一样的。但是，我为任何变量更改了global $wpdb; $nome = ""; $email = ""; $estilo = ""; $experiencia = ""; $altura = ""; $peso = ""; //VÁRIÁVEIS if(!empty($_POST)){ $nome = $_POST['nome']; $email = $_POST['email']; $estilo = $_POST['estilo']; $experiencia = $_POST['experiencia']; $altura = $_POST['altura']; $peso = $_POST['peso']; cadastrar($nome,$email,$estilo,$experiencia,$altura,$peso); calcularIMC($estilo,$experiencia,$altura,$peso); } function cadastrar($nome,$email,$estilo,$experiencia,$altura,$peso){ //INSERE OS DADOS NO BANCO try{ $wpdb->insert( "INSERT INTO aa_minhaprancha("."nome, email, estilo, experiencia, altura, peso) VALUES (". ":nome', ':email', ':estilo', ':experiencia', ':altura', ':peso')"); if($wpdb->rowCount() > 0) return true; else return false; }catch(PDOException $e){ echo "Erro ao incluir na tabela categoria ".$e->getMessage(); } }。

Answer 1

在wordpress中，引用是写的：

<?php $wpdb->insert( $table, $data, $format ); ?>

其中$ data和$ format是数组。

Answer 2

首先，您应该阅读有关如何正确使用$wpdb->insert()

的文档

  $nome = "";
  $email = "";
  $estilo = "";
  $experiencia = "";
  $altura = "";
  $peso = "";

  //VÁRIÁVEIS 
  if(!empty($_POST)){     
     $nome = $_POST['nome'];
     $email = $_POST['email'];
     $estilo = $_POST['estilo'];
     $experiencia = $_POST['experiencia'];
     $altura = $_POST['altura'];
     $peso = $_POST['peso'];


     cadastrar($nome,$email,$estilo,$experiencia,$altura,$peso);
     calcularIMC($estilo,$experiencia,$altura,$peso);

  }    

function cadastrar($nome,$email,$estilo,$experiencia,$altura,$peso){          //INSERE OS DADOS NO BANCO

        // the WPDB class is already setup for us let's make it accessible
        global $wpdb;

        // the name of our table
        $table = 'aa_minhaprancha';

        // data is an array with the format column_name => data
        $data = array(
          'nome' => $nome,
          'email' => $email,
          'estilo' => $estilo,
          'experiencia' => $experiencia,
          'altura' => $altura,
          'peso' => $peso,
        );

        // run the insert
        $inserted = $wpdb->insert( $table, $data );

        // if it didn't update get the error
        if ( ! $inserted ) {
          $wpbb->print_error();
        }

    }

根据表格的设置，您可能需要在插入时添加额外的$format参数。这是要映射到$data

中每个值的格式数组

如何在wordpress数据库中连接和插入数据？

2 个答案: