Soo使用扩展时间任务创建了一个计时器。
label_1.addMouseListener(new MouseAdapter() {
@Override
public void mouseClicked(MouseEvent arg0) {
label_1.setVisible(false);
label_2.setVisible(true);
timer.purge();
class MyTimeTask extends TimerTask
{
public void run(){
genReelNumbers();
laa++;
if(laa==50){
timer.cancel();
timer.purge();
laa=0;
label_1.setVisible(true);
label_2.setVisible(false);}}}
timer.purge();
timer.schedule(new MyTimeTask(), 0, 50);}});
但是我已经取消了计时器的错误!正如你所看到我已经尝试使用purge(),soo它取消了“已取消”的计时器(不知道是否确实如此)。我想每次按下标签时都使用这个计时器!有什么想法吗?
答案 0 :(得分:2)
首先,这看起来是一个Swing应用程序,如果是这样,你不应该使用java.util.Timer和java.util.TimerTask,因为Swing是单一的thread,上面的两个类创建一个或多个新线程来实现它们的动作,这意味着在这个线程上不会调用应该在Swing事件线程上调用的重要代码。这有可能导致有害的间歇性和难以调试的线程异常被抛出。而是使用javax.swing.Timer。然后要停止此计时器,只需在其上调用stop()
,然后重新启动它,只需在其上调用start()
即可。有关详情,请阅读:How To Use Swing Timers。
例如,我不能100%确定你应该做什么代码,但它可能看起来像:
// warning: code not compile- nor run-tested
label_1.addMouseListener(new MouseAdapter() {
@Override
public void mouseClicked(MouseEvent arg0) {
label_1.setVisible(false);
label_2.setVisible(true);
// assuming a javax.swing.Timer field named timer
if (timer != null && timer.isRunning()) {
// if the timer is not null and it's running, stop it:
timer.stop();
}
// TIMER_DELAY is an int constant that specifies the delay between "ticks"
timer = new Timer(TIMER_DELAY, new ActionListener() {
@Override // this method will be called repeatedly, every TIMER_DELAY msecs
public void actionPerformed(ActionEvent e) {
genReelNumbers();
laa++;
if(laa==50){
timer.stop();
// timer.purge();
laa=0;
label_1.setVisible(true);
label_2.setVisible(false);
}
}
});
timer.start();
}
});
答案 1 :(得分:0)
答案 2 :(得分:-1)
我按照@Hovercraft的建议改为javax.swing.Timer
结果是这样的:
//The variable "taxa" is the amount of times that i want it to do the task
javax.swing.Timer time1 = new javax.swing.Timer(taxa, new ActionListener() {
public void actionPerformed(ActionEvent e) {
genReelNumbers();
}
});
//starts the timer
time1.start();
//New timertask
TimerTask tt = new TimerTask() {
@Override
public void run() {
//stops the timer
time1.stop();
label_2.setVisible(false);
label_1.setVisible(true);
verificarodas();
}
};
Timer time = new Timer(true);
// the 2000 is how long i want to do the task's
//if i changed to 3000 it would take 3 seconds (remember it has to be a value on miliseconds) to do the 15 times, and soo on
time.schedule(tt, 2000);