我想在锚点html中匹配一个url并返回url。子域和路径文件总是在变化。
这是网址。
https://regex101.com/r/gB4bB8/3
我希望它仅返回网址https://s04.solidfilesusercontent.com/NGU0MGIwZTg1MDU0MjI5YzE3YzM3NDQ4ZWJhNjVhN2Y3ZGVmN2EwNDoxYkFmRkY6ODZvb29qRG8tdFluMXl2TU1hR1dBN19ockt3/v8grz2RpkMkWd/As_The_Gods_Will_%282014%29-1.mp4
$matches = "";
$regex = '/<a.+?href=("|\')(.+?)\1/i';
$url = "<a target='blank' href='https://s04.solidfilesusercontent.com/NGU0MGIwZTg1MDU0MjI5YzE3YzM3NDQ4ZWJhNjVhN2Y3ZGVmN2EwNDoxYkFmRkY6ODZvb29qRG8tdFluMXl2TU1hR1dBN19ockt3/v8grz2RpkMkWd/As_The_Gods_Will_%282014%29-1.mp4'>https://s04.solidfilesusercontent.com/NGU0MGIwZTg1MDU0MjI5YzE3YzM3NDQ4ZWJhNjVhN2Y3ZGVmN2EwNDoxYkFmRkY6ODZvb29qRG8tdFluMXl2TU1hR1dBN19ockt3/v8grz2RpkMkWd/As_The_Gods_Will_%282014%29-1.mp4</a>";
preg_match($regex, $url, $matches);
echo $matches[0];
THX