Question

如何在swift语句中使用更多数组值？

代码：

var array = ["Beer", "Water", "Cola", "Sprite", "Wodka"]

var drinks = "" // The variable drinks updates with a pickerView of the above array

func doSomethingWithArray() {

    if drinks == array[1] {

        print("this is water, so no sugar in it")

    } else if drinks == array[2,3] {

        print("This drink contains sugar")

    } else {
        print("This drink is alcoholic")
}

是否有一种简单的方法可以在else if语句中使用多个数组值？但那是一种有效的方式。：）

Answer 1

如果我理解你的问题是正确的，那么就可以使用contains。

let myDrink = "Cola"
let sweetDrinks = ["Cola", "Sprite"]

if sweetDrinks.contains(myDrink) {
    print(myDrink, "is a sweet drink")
}

要进行更复杂的检查，请使用Set。例如：

let myDrinks = Set(["Beer", "Water", "Cola", "Vodka", "Tonic"])
let sweetDrinks = ["Cola", "Sprite", "Tonic"]

// Show myDrinks which are also sweet drinks
let mySweetDrinks = myDrinks.intersect(sweetDrinks)
print(mySweetDrinks) // prints ["Tonic", "Cola"]

Answer 2

在评论中跟踪对话之后，此代码应该可以正常工作

struct Drink {
    var name: String
    var haveSugar: Bool
    var haveAlcohol: Bool

    init (name: String, haveSugar: Bool, haveAlcohol: Bool) {
        self.name = name
        self.haveSugar = haveSugar
        self.haveAlcohol = haveAlcohol
    }
}

var drinks = [Drink(name: "Beer", haveSugar: true, haveAlcohol: true), Drink(name: "Water", haveSugar: false, haveAlcohol: false), Drink(name: "Sprite", haveSugar: true, haveAlcohol: false), Drink(name: "Wodka", haveSugar: true, haveAlcohol: true)]

func checkDrink(drink: Drink) {
    if drink.haveSugar == true {
        print("\(drink.name) have sugar!")
    }
    else {
        print("\(drink.name) doesn't have sugar")
    }
}

checkDrink(drinks[1])

可能性数组（快速）

2 个答案: