Question

你能告诉我如何在整数数组中删除给定数字之前和之后的n个元素吗？例如，我们有1 2 2 4 2 2 2 9并且必须在数字＃34; 4＆＃34;之前和之后删除2个元素。所以它将离开1429.我试图想出一些东西，但......没什么。

var sequenceOfNums = Console.ReadLine().Split(' ').Select(int.Parse).ToList();
var specials = Console.ReadLine().Split(' ').Select(int.Parse).ToArray();
int bombNum = specialBombNum[0];
int power = specialBombNum[1];

for (int i = 0; i < sequenceOfNums.Count; i++) {
  sequenceOfNums.RemoveRange(bombNum, sequenceOfNums.IndexOf(bombNum + power));
  sequenceOfNums.Remove(bombNum);
}

Answer 1

这应该有效：

var sequenceOfNums = new List<int> {1, 2, 2, 4, 2, 2, 2, 9};

int bombNum = 4;
int power = 2;

//Get the index of the special number
int locationOfSpecialNumber = sequenceOfNums.IndexOf(bombNum);

//Starting from (index of special number - [power]), remove [power] elements
sequenceOfNums.RemoveRange(locationOfSpecialNumber - power, power);

//Starting from (index of special number + 1), remove [power] elements.
//We subtract [power] from the starting index to account for the
//[power] elements we removed in the previous statement
sequenceOfNums.RemoveRange(locationOfSpecialNumber + 1 - power, power);

删除给定数字前后的n个元素

1 个答案: