JSONExcepetion尝试从php

时间:2016-06-08 15:20:43

标签: php android jsonexception

我的Android应用程序出现错误,每次运行时都会抛出JSONException

这是我的PHP代码,如果我的表中 type 的每个值等于'run',它只返回true:

$userId = $_POST["userId"]; 
$statement = mysqli_prepare($con, "SELECT type FROM performance WHERE userId = ?");
mysqli_stmt_bind_param($statement, "i", $userId);
mysqli_stmt_execute($statement);
mysqli_stmt_store_result($statement);
mysqli_stmt_bind_result($statement,  $type);
$correct = false;  
while(mysqli_stmt_fetch($statement)){
    if(strcmp($type,"run")==0)     $correct = true;
    else     $correct = false;
}
mysql_close($statement);
echo json_encode($correct);

这是我的Android代码,我正在使用Volley库:

Response.Listener<String> responseListener = new Response.Listener<String>(){
    @Override
    public void onResponse(String response) {
        try {
            JSONObject jsonResponse = new JSONObject(response);
            boolean success = jsonResponse.getBoolean("correct");
            if (success)
                /*do something*/
            else
                /*do something else*/
        }catch (JSONException e) {
            e.printStackTrace();
        }    
    }    

但是,每次我运行我的应用程序都称为JSONException,它说是

org.json.JSONException: Value <br of type java.lang.String cannot be converted to JSONObject

任何人都可以帮助我吗?

0 个答案:

没有答案