Question

declare @hdoc int, @xmlchar nvarchar(max)
set @xmlchar = '<root> <row _Fld394=" 61640200" /></root>'
exec sp_xml_preparedocument @hdoc out, @xmlchar

select _Fld394
from openxml(@hdoc, '/root/row')
with
(_Fld394 nvarchar(9) '@_Fld394')

exec sp_xml_removedocument @hdoc
//result = '61640200'
//must be = ' 61640200'

如果你看看_Fld394录制了9个字符 - 来自前方空间提取时，用空格剪掉左边。

如何解决问题？

Answer 1

declare @hdoc int, @xmlchar nvarchar(max)
set @xmlchar = '<root> <row _Fld394="     asas" /><row _Fld394="" /></root>'
exec sp_xml_preparedocument @hdoc out, @xmlchar

select   QuoteName(A)                       AS A
    ,QuoteName(B.value('.'          ,'varchar(9)')) AS B
    ,QuoteName(C.value('*[1]/@_Fld394'  ,'varchar(9)')) AS C
from openxml(@hdoc, '/root/row')
with (A varchar(9) '@_Fld394', B xml '@_Fld394/text()', C xml '.')

exec sp_xml_removedocument @hdoc

Answer 2

我认为这是sp_xml_preparedocument的一个已知问题。您可以使用 编码空格：

set @xmlchar = '<root> <row _Fld394="&#160;61640200" /></root>'

或（假设SQL 2005或更高版本）使用较新的样式XML数据类型并处理：

declare @xmlchar xml
set @xmlchar = '<root> <row _Fld394=" 61640200" /></root>'

select x.fld.value('@_Fld394','varchar(100)')
 from @xmlchar.nodes('//root/row') as x(fld)

在提取XML时截断空格

2 个答案: