Question

如何添加＆＃34; for＆＃34;数组内部的函数输出？感谢

for($idid = 0; $idid <= $say; $idid++) {
    echo "@";
    print_r($string[$idid]['screen_name']);
    echo " ";
}

$url = "https://api.twitter.com/1.1/statuses/update.json";
$twitter = new TwitterAPIExchange($settings);
$requestMethod = 'POST';
$response = $twitter->setPostfields(
    array(
        'status' => "I NEED TO ADD FOR FUNCTION OUTPUT HERE")
)
    ->buildOauth($url, $requestMethod)
    ->performRequest();

Answer 1

您应该保存为变量而不是像这样打印到屏幕：

clearTimeout(timeout);

来自$status = ""; for($idid = 0; $idid <= $say; $idid++) { $status .= "@"; $status .= print_r($string[$idid]['screen_name'], true); $status .= " "; }的第二个参数是返回输出而不是打印它。您可以查看更多here

然后在数组中使用print_r变量，如下所示：

$status

Answer 2

您只需要在for循环中构建一个字符串，然后在API调用中引用它：

$status = '';
for ($idid = 0; $idid <= $say; $idid++) {

    // Only keep if you're also printing output to the screen
    echo "@";
    print_r($string[$idid]['screen_name']);
    echo " ";

    // New Code
    $status .= '@' . $string[$idid]['screen_name'] . ' ';
}

$url = "https://api.twitter.com/1.1/statuses/update.json";
$twitter = new TwitterAPIExchange($settings);
$requestMethod = 'POST';
$response = $twitter->setPostfields(array(
        'status' => trim($status)
    ))->buildOauth($url, $requestMethod)
    ->performRequest();

Answer 3

不是打印字符串，只需将它们保存在变量中供以后使用。

$var = '';
for($idid = 0; $idid <= $say; $idid++) {
    $var = $var . "@";
    $var = $var . print_r($string[$idid]['screen_name'], true);
    $var = $var . " ";
}

...

$response = $twitter->setPostfields(
    array(
        'status' => $var)
)

编辑：print_r（）接受第二个参数，如果这是真的，则输出以字符串形式返回而不是打印。

句点用于字符串连接，并且有一些缩写，即 $ var。=＆＃39; ＆＃39;; 而不是 $ var = $ var。＆＃39; ＆＃39 ;; 。但是现在为了清楚起见，我明确地编写了代码。

Answer 4

使for循环中的内容成为变量。像这样：

$output = "";
for($idid = 0; $idid <= $say; $idid++) {
    $output .= "@".print_r($string[$idid]['screen_name'], true)." "; // true makes it return the content instead of printing it
}

$url = "https://api.twitter.com/1.1/statuses/update.json";
$twitter = new TwitterAPIExchange($settings);
$requestMethod = 'POST';
$response = $twitter->setPostfields(
    array(
        'status' => $output)
)
    ->buildOauth($url, $requestMethod)
    ->performRequest();

数组内的PHP代码

4 个答案: