Question

我有像这样的SQL查询结果

id | subId |  code |  name  |      response
1  |     1 |   abc |    xyz |     "Whatever"
1  |     1 |   abc |    xyz |     "Whatever2"
1  |     2 |   def |    qrt |     "Whatever3"
1  |     2 |   def |    qrt |     "Whatever4"

我需要显示前四列（id，subid，code，name）一次（基于id和subid），其中响应id和响应值就像它一样

id | subId |  code |  name  |    responsevalue
1  |     1 |   abc |    xyz |     "Whatever"
                            |     "Whatever2"
1  |     2 |   def |    qrt |     "Whatever3"
                            |     "Whatever4"

Answer 1

使用ROW_NUMBER（）获取组中记录的行数，然后使用CASE语句输出所有非第一条记录（行号＆lt;＆gt; 1）的NULL。

WITH T1 AS
(
   SELECT T.*,
          ROW_NUMBER() OVER (PARTITION BY ID ORDER BY responseid ) as rn
   FROM T
)

SELECT 
   CASE WHEN rn=1 THEN ID ELSE NULL END as ID,
   CASE WHEN rn=1 THEN SubId ELSE NULL END as SubID,
   CASE WHEN rn=1 THEN Code ELSE NULL END as Code,
   CASE WHEN rn=1 THEN Name ELSE NULL END as Name,
   responseId,
   response_value
FROM T1
ORDER BY T1.id,rn

一次sql如何在列集中显示相同的值

1 个答案: