假设这是我的弹性搜索结构:
{
"_index": "my_index",
"_type": "person",
"_id": "ID",
"_source": {
...DATA...
}
}
{
"_index": "my_index",
"_type": "result",
"_id": "ID",
"_source": {
"personID": "personID"
"date": "timestamp",
"result": "integer",
"speciality": "categoryID"
}
}
我希望根据以下内容获得最多“最流行”的人:
我正在考虑使用_score,但我不知道如何使用从“result”类型的文档聚合的某些值来影响分数。这就是我想要实现的目标
POST my_index/_search?search_type=dfs_query_then_fetch
{
"size": 10,
"query": {
"function_score": {
"query": {
"bool": {
"must": [
{
"term": {
"_type": {
"value": "person"
}
}
}
]
}
}
},
"functions": [
{
"field_value_factor": {
"field": {
"query": {
//competitions in the last 30 days
},
"aggs": {
//cout
}
},
"factor": 1
},
"weight": 0.1
}
]
}
}
这是一个好方法吗?
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