Question

以下是我的表结构

CREATE TABLE IF NOT EXISTS `physicians` (
  `physician_id` bigint(20) NOT NULL AUTO_INCREMENT,
  `user_id` bigint(20) NOT NULL,
  `physician_gender` varchar(10) NOT NULL,
  `physician_dob_date` int(11) NOT NULL,
  `physician_dob_month` int(11) NOT NULL,
  `physician_dob_year` year(4) NOT NULL,
  `physician_profession` varchar(50) NOT NULL,
  `medical_specialty` varchar(100) NOT NULL,
  `medical_school` varchar(100) NOT NULL,
  `traning_year` year(4) NOT NULL,
  `physician_minc` varchar(20) NOT NULL,
  `physician_country` varchar(100) NOT NULL,
  `physician_state` varchar(60) NOT NULL,
  `physician_city` varchar(60) NOT NULL,
  `physician_address` varchar(100) NOT NULL,
  `physician_postal_code` varchar(10) NOT NULL,
  `physician_phone_number` varchar(20) NOT NULL,
  `physician_default_msg` longtext NOT NULL,
  PRIMARY KEY (`physician_id`),
  KEY `user_id` (`user_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ;

我正在执行一个查询，它显示我的列不能为空，下面是我的查询

INSERT INTO `physicians` (`user_id`, `physician_gender`, `physician_dob_date`, `physician_dob_month`, `physician_dob_year`, `physician_profession`, `medical_specialty`, `medical_school`, `traning_year`, `physician_minc`, `physician_country`, `physician_state`, `physician_city`, `physician_address`, `physician_postal_code`, `physician_phone_number`, `physician_default_msg`) VALUES (4, 'Female', '5', '7', '1955', '3', '2', '1', '1965', NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL)

错误 - 列＆＃39; physician_minc＆＃39;不能为空

physician_minc不是必填字段。我该如何解决这个问题？

Answer 1

您已将非空值定义为＆＃39; physician_minc＆＃39;：

`physician_minc` varchar(20) NOT NULL,

如何将null值传递给它。首先，您需要将physician_minc列设为null，然后才能传递所需的空值。

`physician_minc` varchar(20) NULL,

Answer 2

创建表时，使用NOT NULL将列定义为必需列。您应该将所有非强制的列更改为NULL。

对于您的插入代码，我假设只有前10个字段是必需的，因此要正确插入数据，您的表生成代码应如下所示：

CREATE TABLE IF NOT EXISTS `physicians` (
 `physician_id` bigint(20) NOT NULL AUTO_INCREMENT,
 `user_id` bigint(20) NOT NULL,
 `physician_gender` varchar(10) NOT NULL,
 `physician_dob_date` int(11) NOT NULL,
  `physician_dob_month` int(11) NOT NULL,
  `physician_dob_year` year(4) NOT NULL,
  `physician_profession` varchar(50) NOT NULL,
  `medical_specialty` varchar(100) NOT NULL,
  `medical_school` varchar(100) NOT NULL,
  `traning_year` year(4) NOT NULL,
  `physician_minc` varchar(20) NULL,
  `physician_country` varchar(100) NULL,
  `physician_state` varchar(60)  NULL,
  `physician_city` varchar(60) NULL,
  `physician_address` varchar(100)  NULL,
  `physician_postal_code` varchar(10)  NULL,
  `physician_phone_number` varchar(20)  NULL,
  `physician_default_msg` longtext  NULL,
  PRIMARY KEY (`physician_id`),
  KEY `user_id` (`user_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ;

Answer 3

不要将physician_minc定义为not null

Answer 4

插入的最后一个值是NULL，但在表创建中声明为非null，因此出错。如果physician_minc不是必需的，那么在表创建中通过将physician_minc varchar（20）NOT NULL替换为physician_minc varchar（20）NULL来允许它为NULL，

Answer 5

ALTER TABLE physicians CHANGE `physician_minc` `physician_minc` VARCHAR(20) NULL;

Answer 6

如果您不想输入值，只是不要使该列不为空，请跳过此语句，否则在其中输入值是比较的。

Answer 7

更新您的表格：

ALTER TABLE `physicians` 
CHANGE `physician_minc` `physician_minc` VARCHAR(20) CHARACTER 
SET latin1 COLLATE latin1_swedish_ci NULL;

Answer 8

与查询不同，如果列不支持空值，则此查询将用空字符串替换null。：

INSERT INTO `physicians` (`user_id`, `physician_gender`, `physician_dob_date`, `physician_dob_month`, `physician_dob_year`, `physician_profession`, `medical_specialty`, `medical_school`, `traning_year`, `physician_minc`, `physician_country`, `physician_state`, `physician_city`, `physician_address`, `physician_postal_code`, `physician_phone_number`, `physician_default_msg`) SELECT 4, 'Female', '5', '7', '1955', '3', '2', '1', '1965', NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL;

列不能为null Mysql

8 个答案: