Angular $ q有两个“then”：如果第一个到达错误处理程序，那么第二个会被调用吗？

Question

$q.all([firstPromise, secondPromise])
    .then(successHandler1, errorHandler1)
    .then(successHandler2, errorHandler2);

调用errorHandler1后会调用successHandler2吗？

Answer 1

如果值从拒绝回调返回，则将执行成功回调，如果抛出错误，则将执行错误回调。

var app = angular.module('myApp', [])
app.controller('myController', function ($q) {
  $q(function (resolve, reject) {
    reject('1');
  })
  .then(
    function(resolve) {
      console.log('resolve 1');
      return 'resolve 1';
    },
    function(reject) {
      console.log('reject 1');
      throw 'reject 1'
    })
  .then(
    function(resolve) {
      console.log('resolve 2');
    },
    function(reject) {
      console.log('reject 2');
      return 'reject 2'
    })
  .then(
    function(resolve) {
      console.log('resolve 3');

    },
    function(reject) {
      console.log('reject 3');
    })
})

http://plnkr.co/edit/k2UprgZd0J4RP8PtDye2?p=preview

控制台：

拒绝1

拒绝2

解决3

Answer 2

电话的顺序是：

successHandler1然后是successHandler2 要么 errorHandler1是errorHandler2