Question

我希望运行一个Python脚本，寻找某人在指定的时间段内（比如一周）与之交互。如果有人与之交互，它将继续寻找互动的另一个循环。如果某人没有与之互动，则会开始执行某些操作。

我已经使用模块signal启动了这样的脚本（并且示例超时为20秒），但是超时似乎没有起作用;该脚本立即启动到非交互操作。出了什么问题？有没有更好的方法解决这个问题？

#!/usr/bin/env python

import propyte

import signal
import time

def main():

    response = "yes"
    while response == "yes":
        response = get_input_nonblocking(
            prompt          = "ohai?",
            timeout         = 20 #604800 s (1 week)
        )
    print("start non-response procedures")
    # do things

def alarm_handler(signum, frame):
    raise Exception

def get_input_nonblocking(
    prompt          = "",
    timeout         = 20, # seconds
    message_timeout = "prompt timeout"
    ):
    signal.signal(signal.SIGALRM, alarm_handler)
    signal.alarm(timeout)
    try:
        response = propyte.get_input(prompt)
        signal.alarm(0)
        return response
    except Exception:
        print(message_timeout)
    signal.signal(signal.SIGALRM, signal.SIG_IGN)
    return ""

if __name__ == '__main__':
    main()

Answer 1

您可以简单地写一下：

import signal
TIMEOUT = 20 * 60 # secs to wait for interaction

def interrupted(signum, frame):
    "called when read times out"
    print('Exiting')

signal.signal(signal.SIGALRM, interrupted)

def i_input():
    try:
            print('You have 20 minutes to interact or this script will cease to execute')
            foo = input()
            return foo
    except:
            # timeout
            return

# set alarm
signal.alarm(TIMEOUT)

inp = i_input()

# disable the alarm if not wanted any longer
# signal.alarm(0)

如何用Python编写“死人的转换”，监视在指定时间内的交互？

1 个答案: