从正则表达式中提取匹配项

Question

给定一个字符串

""Being Ordered Around by You Makes Me Really Angry Somehow!!!" "Whaddaya Mean, 'Somehow'!!?""
""Omae ni Meirei Sareru no wa Nanka Haratatsu!!!" "Nankatte Nani!!?""

如何在每组双引号之间提取字符串（包括中间的双引号），以便我得到两个单独的字符串，如：

"Being Ordered Around by You Makes Me Really Angry Somehow!!!" "Whaddaya Mean, 'Somehow'!!?"

和

"Omae ni Meirei Sareru no wa Nanka Haratatsu!!!" "Nankatte Nani!!?"

我正在使用的正则表达式是"(.*)(.*)"，根据此工具，它匹配正常

我的问题是将两个匹配作为单独的字符串提取。

var pattern =  new Regex(@"""(.*)(.*)""", RegexOptions.None);
var matches = pattern.Matches(text);

matches不包含两个元素。我究竟做错了什么？

Answer 1

尝试使用Regex.Match代替Matches和此正则表达式

"("[^"]*")[^"]*("[^"]*")"

它匹配"，捕获跟随"以及下一个"的所有内容。然后它匹配到下一个"的任何内容。然后重复 - 捕获以下"以及包含下一个"的所有内容。最后它匹配终止"。这两个字符串，包括它们的周围引号，位于捕获组1和1中。 2。

这样的事情：

    string s1 = "\"\"Being Ordered Around by You Makes Me Really Angry Somehow!!!\" \"Whaddaya Mean, 'Somehow'!!?\"\"",
           s2 = "\"\"Omae ni Meirei Sareru no wa Nanka Haratatsu!!!\" \"Nankatte Nani!!?\"\"";

    Console.WriteLine("Before 1  : " + s1);
    Console.WriteLine("Before 2  : " + s2);

    Regex r = new Regex("\"(\"[^\"]*\")[^\"]*(\"[^\"]*\")\"");
    Match m = r.Match(s1);
    Console.WriteLine("After 1.1 : " + m.Groups[1].Value);
    Console.WriteLine("After 1.2 : " + m.Groups[2].Value);

    m = r.Match(s2);
    Console.WriteLine("After 2.1 : " + m.Groups[1].Value);
    Console.WriteLine("After 2.2 : " + m.Groups[2].Value);

See it here at ideone

Answer 2

您可以尝试this regex

dispatch_sync(dispatch_get_main_queue(), {
    delegate.requestSucceededWithJsonResponse(responseObject!)
});

并迭代MatchCollection类提供的匹配。