我有一个代码可以打印正在运行的实例的公共IP,
regions = ['us-east-1','us-west-1','us-west-2','eu-west-1','sa-east-1','ap-southeast-1','ap-southeast-2','ap-northeast-1']
for region in regions:
client = boto3.client('ec2',aws_access_key_id=ACCESS_KEY,aws_secret_access_key=SECRET_KEY,region_name=region,)
addresses_dict = client.describe_addresses()
for eip_dict in addresses_dict['Addresses']:
if 'PrivateIpAddress' in eip_dict:
print eip_dict['PublicIp']
这很好,现在我也要打印tag name
并将其存储在另一个字典中,我知道我可以通过以下方式完成:
regions = ['us-east-1','us-west-1','us-west-2','eu-west-1','sa-east-1','ap-southeast-1','ap-southeast-2','ap-northeast-1']
for region in regions:
client = boto3.client('ec2',aws_access_key_id=ACCESS_KEY,aws_secret_access_key=SECRET_KEY,region_name=region,)
dex_dict = client.describe_tags()
for dexy_dict in dex_dict['Tags']:
print dexy_dict['Value']
问题是如何将它组合在一个函数中并使用2个dict:一个用于存储IP,另一个用于存储标记名称?请帮助
答案 0 :(得分:0)
尝试以下代码,它会为您提供一个字典,其中键为InstanceId
,值为[PublicIP, Name]
列表。
import boto3
def instance_info():
instance_information = {}
ip_dict = {}
client = boto3.client('ec2')
addresses_dict = client.describe_addresses().get('Addresses')
for address in addresses_dict:
if address.get('InstanceId'):
instance_information[address['InstanceId']] = [address.get('PublicIp')]
dex_dict = client.describe_tags().get('Tags')
for dex in dex_dict:
if instance_information.get(dex['ResourceId']):
instance_information[dex['ResourceId']].append(dex.get('Value'))
for instance in instance_information:
if len(instance_information[instance]) == 2:
ip_dict[instance_information[instance][0]] = instance_information[instance][1]
else:
ip_dict[instance_information[instance][0]] = ''
return instance_information, ip_dict