我有一个ListBox,我想为列表中的每个项目添加一个上下文菜单。我已经看到“解决方案”右键单击选择一个项目并禁止上下文菜单,如果在空白区域,但这个解决方案感觉很脏。
有没有人知道更好的方法?
答案 0 :(得分:29)
稍微详细说明一下Frans所说的内容......即使ListBox拥有ContextMenuStrip,您仍然可以在菜单条打开时自定义它们。因此,根据列表框中的鼠标位置自定义内容 下面的示例基于鼠标右键单击选择列表框中的项目,然后根据用户右键单击的项目自定义上下文菜单条。这是一个简单的示例,但应该让您前进:将一个列表框添加到表单并添加以下代码:
print(" #region Private Members
private ContextMenuStrip listboxContextMenu;
#endregion
private void Form1_Load( object sender, EventArgs e )
{
//assign a contextmenustrip
listboxContextMenu = new ContextMenuStrip();
listboxContextMenu.Opening +=new CancelEventHandler(listboxContextMenu_Opening);
listBox1.ContextMenuStrip = listboxContextMenu;
//load a listbox
for ( int i = 0; i < 100; i++ )
{
listBox1.Items.Add( "Item: " + i );
}
}
private void listBox1_MouseDown( object sender, MouseEventArgs e )
{
if ( e.Button == MouseButtons.Right )
{
//select the item under the mouse pointer
listBox1.SelectedIndex = listBox1.IndexFromPoint( e.Location );
if ( listBox1.SelectedIndex != -1)
{
listboxContextMenu.Show();
}
}
}
private void listboxContextMenu_Opening( object sender, CancelEventArgs e )
{
//clear the menu and add custom items
listboxContextMenu.Items.Clear();
listboxContextMenu.Items.Add( string.Format( "Edit - {0}", listBox1.SelectedItem.ToString() ) );
} ");
希望有所帮助。 -Mike
答案 1 :(得分:5)
这样菜单会弹出鼠标旁边的
private string _selectedMenuItem;
private readonly ContextMenuStrip collectionRoundMenuStrip;
public Form1()
{
var toolStripMenuItem1 = new ToolStripMenuItem {Text = "Copy CR Name"};
toolStripMenuItem1.Click += toolStripMenuItem1_Click;
var toolStripMenuItem2 = new ToolStripMenuItem {Text = "Get information on CR"};
toolStripMenuItem2.Click += toolStripMenuItem2_Click;
collectionRoundMenuStrip = new ContextMenuStrip();
collectionRoundMenuStrip.Items.AddRange(new ToolStripItem[] {toolStripMenuItem1, toolStripMenuItem2 });
listBoxCollectionRounds.MouseDown += listBoxCollectionRounds_MouseDown;
}
private void toolStripMenuItem2_Click(object sender, EventArgs e)
{
var info = GetInfoByName(_selectedMenuItem);
MessageBox.Show(info.Name + Environment.NewLine + info.Date);
}
private void toolStripMenuItem1_Click(object sender, EventArgs e)
{
Clipboard.SetText(_selectedMenuItem);
}
private void myListBox_MouseDown(object sender, MouseEventArgs e)
{
if (e.Button != MouseButtons.Right) return;
var index = myListBox.IndexFromPoint(e.Location);
if (index != ListBox.NoMatches)
{
_selectedMenuItem = listBoxCollectionRounds.Items[index].ToString();
collectionRoundMenuStrip.Show(Cursor.Position);
collectionRoundMenuStrip.Visible = true;
}
else
{
collectionRoundMenuStrip.Visible = false;
}
}
答案 2 :(得分:4)
没有其他方法:上下文菜单不归列表框中的项目所有,而是由列表框本身拥有。它类似于treeview控件,它也拥有上下文菜单而不是treenode。因此,每当选择列表框中的项目时,根据所选项目设置列表框的上下文菜单。
答案 3 :(得分:4)
这是我的解决方案:
listBox_Usernames.ContextMenuStrip = contextMenuStripRemove;
listBox_Usernames.MouseUp += new MouseEventHandler(listBox_Usernames_MouseUp);
void listBox_Usernames_MouseUp(object sender, MouseEventArgs e)
{
int index = listBox_Usernames.IndexFromPoint(e.Location);
if (e.Button == System.Windows.Forms.MouseButtons.Right)
{
if (index != ListBox.NoMatches)
{
if (listBox_Usernames.SelectedIndex == index)
{
listBox_Usernames.ContextMenuStrip.Visible = true;
}
else
{
listBox_Usernames.ContextMenuStrip.Visible = false;
}
}
else
{
listBox_Usernames.ContextMenuStrip.Visible = false;
}
}
else
{
listBox_Usernames.ContextMenuStrip.Visible = false;
}
}
答案 4 :(得分:3)
在XAML中,它显示如下:
<ListBox> <ListBox.ContextMenu> <ContextMenu> <MenuItem Header="Add User..."/> <MenuItem Header="Edit..."/> <MenuItem Header="Disable"/> </ContextMenu> </ListBox.ContextMenu> </ListBox>
答案 5 :(得分:1)
如果只是启用或禁用上下文菜单项的问题,只有在启动上下文菜单时才这样做,而不是每次列表框选择发生变化时都可能更有效:
myListBox.ContextMenu.Popup += new EventHandler(myContextPopupHandler);
private void myContextPopupHandler(Object sender, System.EventArgs e)
{
if (SelectedItem != null)
{
ContextMenu.MenuItems[1].Enabled = true;
ContextMenu.MenuItems[2].Enabled = true;
}
else
{
ContextMenu.MenuItems[1].Enabled = false;
ContextMenu.MenuItems[2].Enabled = false;
}
}
答案 6 :(得分:1)
这个最好......
using System.Windows.Forms;
ContextMenuStrip menu;
this.menu.Items.AddRange(new ToolStripItem[] { this.menuItem });
this.listBox.MouseUp += new MouseEventHandler(this.mouse_RightClick);
private void mouse_RightClick(object sender, MouseEventArgs e)
{
int index = this.listBox.IndexFromPoint(e.Location);
if (index != ListBox.NoMatches)
{
menu.Visible = true;
}
else
{
menu.Visible = false;
}
}
答案 7 :(得分:1)
在一行代码中(更多用于绑定):
var datasource = new BindingList<string>( new List<string>( new string[] { "item1" } ) );
listbox.DataSource = datasource ;
listbox.ContextMenu = new ContextMenu(
new MenuItem[] {
new MenuItem("Delete",
new EventHandler( (s,ev) =>
datasource.Remove(listbox.SelectedItem.ToString())
)
)
});
private void buttonAdd_Click(object sender, EventArgs e)
{
datasource.Add( textBox.Text );
}
答案 8 :(得分:0)
//Create and Initialize the contextMenuStrip component
contextMenuStrip_ListaAulas = new ContextMenuStrip();
//Adding an Item
contextMenuStrip_ListaAulas.Items.Add("Modificar");
//Binding the contextMenuStrip with the ListBox
listBox_Aulas.ContextMenuStrip = contextMenuStrip_ListaAulas;
//The solution below
if (e.Button == System.Windows.Forms.MouseButtons.Right)
{
//select the item under the mouse pointer
listBox_Aulas.SelectedIndex = listBox_Aulas.IndexFromPoint(e.Location);
//if the selected index is an item, binding the context MenuStrip with the listBox
if (listBox_Aulas.SelectedIndex != -1)
{
listBox_Aulas.ContextMenuStrip = contextMenuStrip_ListaAulas;
}
//else, untie the contextMenuStrip to the listBox
else
{
listBox_Aulas.ContextMenuStrip = null;
}
}
答案 9 :(得分:0)
我喜欢这个,这对我来说很有效。
private void contextMenuStrip1_Opening(object sender, CancelEventArgs e)
{
if (Listbox.SelectedItem == null)
e.Cancel = true;
}